复合常量的问题

最新推荐文章于 2025-07-07 11:39:49 发布

最新推荐文章于 2025-07-07 11:39:49 发布 · 246 阅读

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本文通过示例代码展示了如何使用Java将整数转换为二进制、十六进制和八进制字符串，并介绍了按位或运算的应用。具体包括不同进制之间的转换方法及条件判断的实现。

int a = 1; System.out.println(a); System.out.println("Integer.toBinaryString(a)=" + Integer.toBinaryString(a)); System.out.println("Integer.toHexString(a)=" + Integer.toHexString(a)); System.out.println("Integer.toOctalString(a)=" + Integer.toOctalString(a)); a = 2; System.out.println(a); System.out.println("Integer.toBinaryString(a)=" + Integer.toBinaryString(a)); System.out.println("Integer.toHexString(a)=" + Integer.toHexString(a)); System.out.println("Integer.toOctalString(a)=" + Integer.toOctalString(a));

a = 4;
System.out.println(a);
System.out.println("Integer.toBinaryString(a)=" +
Integer.toBinaryString(a));
System.out.println("Integer.toHexString(a)=" + Integer.toHexString(a));
System.out.println("Integer.toOctalString(a)=" +
Integer.toOctalString(a));

a = 8;
System.out.println(a);
System.out.println("Integer.toBinaryString(a)=" +
Integer.toBinaryString(a));
System.out.println("Integer.toHexString(a)=" + Integer.toHexString(a));
System.out.println("Integer.toOctalString(a)=" +
Integer.toOctalString(a));

int b = 1 | 2 | 4 | 8;
System.out.println("1 | 2 | 4 | 8 = " + b);

int b1 = 4;
System.out.println(b1 + " is In " + b + " ? " + ((b1 & b) == b1) );

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