Sql Server按树形结构排序查询表记录（优快云论坛转载）

WITH T AS
(
    SELECT CAST(Tree_Id AS VARCHAR(20)) AS CODE,*,CAST(City_Id AS VARBINARY(MAX)) AS px  FROM Class_City AS A

    WHERE NOT EXISTS(SELECT * FROM Class_City WHERE City_Id=A.Father_Id)

    UNION ALL 

    SELECT CAST(B.Tree_Id+A.Tree_Id AS VARCHAR(20)),A.*,CAST(B.px+CAST(A.City_Id AS VARBINARY) AS VARBINARY(MAX))  FROM Class_City AS A
    JOIN T AS B ON A.Father_Id=B.City_Id

)

SELECT City_Id,HelpCode,City_Name,Class_Class,Father_Id FROM T 

ORDER BY px

以下是论坛中的代码：

--------------------------------------------------------------------------

--  Author : htl258(Tony)

--  Date   : 2010-04-23 02:37:28

--  Version:Microsoft SQL Server 2008 (RTM) - 10.0.1600.22 (Intel X86) 

--          Jul  9 2008 14:43:34 

--          Copyright (c) 1988-2008 Microsoft Corporation

--          Developer Edition on Windows NT 5.1 <X86> (Build 2600: Service Pack 3)

--  Subject: BOM按节点排序应用实例

--------------------------------------------------------------------------

 

--实例1:

--> 生成测试数据表:tb

 

IF NOT OBJECT_ID('[tb]') IS NULL

    DROP TABLE [tb]

GO

CREATE TABLE [tb]([id] INT,[code] NVARCHAR(10),[pid] INT,[name] NVARCHAR(10))

INSERT [tb]

SELECT 1,'01',0,N'服装' UNION ALL

SELECT 2,'01',1,N'男装' UNION ALL

SELECT 3,'01',2,N'西装' UNION ALL

SELECT 4,'01',3,N'全毛' UNION ALL

SELECT 5,'02',3,N'化纤' UNION ALL

SELECT 6,'02',2,N'休闲装' UNION ALL

SELECT 7,'02',1,N'女装' UNION ALL

SELECT 8,'01',7,N'套装' UNION ALL

SELECT 9,'02',7,N'职业装' UNION ALL

SELECT 10,'03',7,N'休闲装' UNION ALL

SELECT 11,'04',7,N'西装' UNION ALL

SELECT 12,'01',11,N'全毛' UNION ALL

SELECT 13,'02',11,N'化纤' UNION ALL

SELECT 14,'05',7,N'休闲装'

GO

--SELECT * FROM [tb]

 

-->SQL查询如下:

 

;WITH T AS

(

    SELECT CAST(CODE AS VARCHAR(20)) AS CODE,*,

        CAST(ID AS VARBINARY(MAX)) AS px 

    FROM tb AS A

    WHERE NOT EXISTS(SELECT * FROM tb WHERE id=A.pid)

    UNION ALL 

    SELECT CAST(B.CODE+A.CODE AS VARCHAR(20)),A.*,

         CAST(B.px+CAST(A.ID AS VARBINARY) AS VARBINARY(MAX))    

    FROM tb AS A

        JOIN T AS B

           ON A.pid=B.id

)

SELECT Code,Name FROM T 

ORDER BY px

/*

Code                 Name

-------------------- ----------

01                   服装

0101                 男装

010101               西装

01010101             全毛

01010102             化纤

010102               休闲装

0102                 女装

010201               套装

010202               职业装

010203               休闲装

010204               西装

01020401             全毛

01020402             化纤

010205               休闲装

 

(14 行受影响)

*/

 

--实例2:

--> 生成测试数据表:tb

IF NOT OBJECT_ID('[tb]') IS NULL
    DROP TABLE [tb]
GO
CREATE TABLE [tb]([id] INT,[parentid] INT,[categoryname] NVARCHAR(10))
INSERT [tb]
SELECT 1,0,'test1' UNION ALL
SELECT 2,0,'test2' UNION ALL
SELECT 3,1,'test1.1' UNION ALL
SELECT 4,2,'test2.1' UNION ALL
SELECT 5,3,'test1.1.1' UNION ALL
SELECT 6,1,'test1.2'
GO
--SELECT * FROM [tb]

-->SQL查询如下:
;WITH T AS
(
    SELECT *,CAST(ID AS VARBINARY(MAX)) AS px 
    FROM tb AS A
    WHERE NOT EXISTS(SELECT * FROM tb WHERE id=A.[parentid])
    UNION ALL 
    SELECT A.*,CAST(B.px+CAST(A.ID AS VARBINARY) AS VARBINARY(MAX))  
    FROM tb AS A
        JOIN T AS B
           ON A.[parentid]=B.id
)
SELECT [id],[parentid],[categoryname] FROM T 
ORDER BY px
/*
id          parentid    categoryname
----------- ----------- ------------
1           0           test1
3           1           test1.1
5           3           test1.1.1
6           1           test1.2
2           0           test2
4           2           test2.1

(6 行受影响)
*/



本文来自优快云博客，转载请标明出处：http://blog.youkuaiyun.com/htl258/archive/2010/04/23/5518166.aspx