众所周知,Java虚拟机根本没有实现goto关键字。我的一个函数需要这样的算法,在一个循环里,如果某一次循环不满足条件,那么整个循环需要重新开始。比如下面的例子,我想连续3次打印出随机数[b]都[/b]是0的情况。
[code] private void incorrectGotoSample() {
int printNum = 3;
Random r = new Random();
int ri = r.nextInt(2);
LABEL: for (int i = 0; i < printNum ; i++) {
ri = r.nextInt(2);
System.out.println("ri = " + ri);
if (ri > 0) {
goto LABEL; // "goto" not realized in Java
}
System.out.println("you are here!");
}
}[/code]
考虑了半天,Java里还是能简单实现这样的想法的。替换方案如下,在外层加一个无限循环,使用break跳出不满足情况时的循环状态,并再次使用break跳出无限循环:
[code]private void gotoSample() {
int printNum = 3;
Random r = new Random();
int ri = r.nextInt(2);
while (true) {
int i = 0;
for (i = 0; i < printNum ; i++) {
ri = r.nextInt(2);
System.out.println("ri = " + ri);
if (ri >= 1) {
break;
}
System.out.println("you are here!");
}
if (i == printNum) {
break;
}
}
}[/code]
程序的某次执行结果如下,显示其满足我们的需要。
[code]ri = 1
ri = 1
ri = 1
ri = 0
you are here!
ri = 1
ri = 1
ri = 1
ri = 1
ri = 0
you are here!
ri = 0
you are here!
ri = 1
ri = 0
you are here!
ri = 0
you are here!
ri = 0
you are here!
[/code]
[code] private void incorrectGotoSample() {
int printNum = 3;
Random r = new Random();
int ri = r.nextInt(2);
LABEL: for (int i = 0; i < printNum ; i++) {
ri = r.nextInt(2);
System.out.println("ri = " + ri);
if (ri > 0) {
goto LABEL; // "goto" not realized in Java
}
System.out.println("you are here!");
}
}[/code]
考虑了半天,Java里还是能简单实现这样的想法的。替换方案如下,在外层加一个无限循环,使用break跳出不满足情况时的循环状态,并再次使用break跳出无限循环:
[code]private void gotoSample() {
int printNum = 3;
Random r = new Random();
int ri = r.nextInt(2);
while (true) {
int i = 0;
for (i = 0; i < printNum ; i++) {
ri = r.nextInt(2);
System.out.println("ri = " + ri);
if (ri >= 1) {
break;
}
System.out.println("you are here!");
}
if (i == printNum) {
break;
}
}
}[/code]
程序的某次执行结果如下,显示其满足我们的需要。
[code]ri = 1
ri = 1
ri = 1
ri = 0
you are here!
ri = 1
ri = 1
ri = 1
ri = 1
ri = 0
you are here!
ri = 0
you are here!
ri = 1
ri = 0
you are here!
ri = 0
you are here!
ri = 0
you are here!
[/code]