数据库中有3个表 teacher 表,student表,tea_stu关系表。
teacher 表 teaID name age
student 表 stuID name age [size=medium][/size]
teacher_student表 teaID stuID
要求用一条sql查询出这样的结果
1.显示的字段要有老师name, age 每个老师所带的学生人数
2 只列出老师age为40以下学生age为12以上的记录
第一题的sql:
select teacher.name,teacher.age,t2.c from (select t.teaID,count(*) c from
(select tea_stu.* from tea_stu,teacher where tea_stu.teaID = teacher.teaID ) as t,
student where t.stuid=student.stuid
第二题的sql:
select teacher.name,t2.c from (select t.teaID,count(*) c from
(select tea_stu.* from tea_stu,teacher where tea_stu.teaID = teacher.teaID and
teacher.age<40) as t,student where t.stuid=student.stuid and student.age>12
group by t.teaID) as t2,teacher where teacher.teaID=t2.teaID;
也可以写成下面这样:
select teacher.teaID, teacher.name, t1.total from teacher,
(select teaID,count(tea_stu.stuID) total from tea_stu, student
where tea_stu.stuID = student.stuID and student.age>12
group by teaID ) as t1
where teacher.teaID = t1.teaID and teacher.age<40 ;
teacher 表 teaID name age
student 表 stuID name age [size=medium][/size]
teacher_student表 teaID stuID
要求用一条sql查询出这样的结果
1.显示的字段要有老师name, age 每个老师所带的学生人数
2 只列出老师age为40以下学生age为12以上的记录
第一题的sql:
select teacher.name,teacher.age,t2.c from (select t.teaID,count(*) c from
(select tea_stu.* from tea_stu,teacher where tea_stu.teaID = teacher.teaID ) as t,
student where t.stuid=student.stuid
第二题的sql:
select teacher.name,t2.c from (select t.teaID,count(*) c from
(select tea_stu.* from tea_stu,teacher where tea_stu.teaID = teacher.teaID and
teacher.age<40) as t,student where t.stuid=student.stuid and student.age>12
group by t.teaID) as t2,teacher where teacher.teaID=t2.teaID;
也可以写成下面这样:
select teacher.teaID, teacher.name, t1.total from teacher,
(select teaID,count(tea_stu.stuID) total from tea_stu, student
where tea_stu.stuID = student.stuID and student.age>12
group by teaID ) as t1
where teacher.teaID = t1.teaID and teacher.age<40 ;