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public String double2String(double d, int fNumber)
{
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if (fNumber < 0)
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fNumber = 0;
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String pattern = null;
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switch (fNumber)
{
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case 0:
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pattern = "#0"; //$NON-NLS-1$
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break;
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default:
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pattern = "#0."; //$NON-NLS-1$
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StringBuffer b = new StringBuffer(pattern);
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for (int i = 0; i < fNumber; i++)
{
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b.append('#');
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}
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pattern = b.toString();
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break;
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}
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DecimalFormat formatter = new DecimalFormat();
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formatter.applyPattern(pattern);
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String value = formatter.format(d);
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return value;
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}
double直接输出时,如果小数点后位数太长会出现字母e,采用本方法转换为string再输出



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