将给定数组按首字符不同排列

给定一个全有数字组成的字符串数组{'2', '13', '24', '51', '19'}，输出效果是：

13, 19

2, 24

51

主要是利用String类的一些方法实现。

//实现将诸如：{'1', '12', '21', '148', '27', '34'}，按首个字符分行输出的功能: //13, 19 //2, 24 //51 public class JudgeAndOutput { public static void judgeAndDisplay (int[] intArray, int key){ String outputString = ""; String tempString = ""; String keyString = String.valueOf(key); for (int i=0; i<intArray.length; i++){ tempString = String.valueOf(intArray[i]); if (tempString.startsWith(keyString)){ outputString += tempString +" "; } } System.out.println("The row with "+ key +" as first is: "+ outputString); } public static void main (String args[]){ int[] intArray = new int[100]; for (int i=1; i<=100; i++){ intArray[i-1] = i; } for (int key=1; key<10; key++){ judgeAndDisplay (intArray, key); } } }

输出结果为：

The row with 1 as first is: 1 10 11 12 13 14 15 16 17 18 19 100 The row with 2 as first is: 2 20 21 22 23 24 25 26 27 28 29 The row with 3 as first is: 3 30 31 32 33 34 35 36 37 38 39 The row with 4 as first is: 4 40 41 42 43 44 45 46 47 48 49 The row with 5 as first is: 5 50 51 52 53 54 55 56 57 58 59 The row with 6 as first is: 6 60 61 62 63 64 65 66 67 68 69 The row with 7 as first is: 7 70 71 72 73 74 75 76 77 78 79 The row with 8 as first is: 8 80 81 82 83 84 85 86 87 88 89 The row with 9 as first is: 9 90 91 92 93 94 95 96 97 98 99

有没有更好的办法呢？