Scala File

原创转载请注明出处：http://agilestyle.iteye.com/blog/2332751

 

package org.fool.scala.basic

import scala.io.Source

object ScalaFile {

  def main(args: Array[String]): Unit = {
    val file = Source.fromFile("HelloScala.iml")
    for (line <- file.getLines()) println(line)

    val url = Source.fromURL("http://spark.apache.org")
    for (line <- url.getLines()) println(line)

  }
}

Console Output