Timus 1139. City Blocks 题解

本文探讨了一架直升机从城市的最西南角飞往最东北角时所覆盖的城市街区数量。通过数学方法解决这一问题,并提供了一个C++实现示例。

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The blocks in the city of Fishburg are of square form. Navenues running south to north and Mstreets running east to west bound them. A helicopter took off in the most southwestern crossroads and flew along the straight line to the most northeastern crossroads. How many blocks did it fly above?
Note.A block is a square of minimum area (without its borders).

Input

The input contains Nand Mseparated by one or more spaces. 1 < N, M< 32000.

Output

The number of blocks the helicopter flew above.

Samples

input output
4 3
4
3 3
2

Hint

The figures for samples:
Problem illustration

Reference - The blog below explaine in detail, but I seem like not quite get it that much:

http://flickeringtubelight.net/blog/2006/08/a-diagonal-through-a-rectangular-grid-of-squares/

But anyway, it's a good explanation. And it should be benefit to read it, maybe you can come up with your own way to understand this approach.

This is a problem that can be approach by many ways. I want to post it because it is very mathematics-related.

I , too, use that formula to solve it.

My suggestion is: if you really have a hard time to deduct that formula, just check the small examples, like n = 2, m = 3, and n = 5, m = 4 and so on.

Below is my C++ solution:

#include <iostream>
using namespace std;

int GCDcityBlocks(int n, int m)
{
	while (m)
	{
		int a = n % m;
		n = m;
		m = a;
	}
	return n;
}

void CityBlocks1139()
{
	int n = 0, m = 0;
	cin>>n>>m;
	n--, m--;
	int k = GCDcityBlocks(n, m);
	int ans = n/k + m/k - 1;
	cout<<ans * k;
}




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