Leetcode Container With Most Water

最新推荐文章于 2020-08-23 15:53:30 发布

最新推荐文章于 2020-08-23 15:53:30 发布 · 126 阅读

本文介绍了一个寻找二维平面上由两条垂直线与x轴形成的能容纳最多水的最大容器的算法。该算法采用双指针法从两端开始逐步向中间逼近，通过比较左右两侧的高度来决定移动哪个指针，以确保宽度减小时能找到更高的线来形成更大的容器。

Container With Most Water

Total Accepted:4630 Total Submissions:15434 My Submissions

Givennnon-negative integersa1,a2, ...,an, where each represents a point at coordinate (i,ai).nvertical lines are drawn such that the two endpoints of lineiis at (i,ai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.

Note: You may not slant the container.

知道原理就是很简单的程序。两边搜索，短板往里走。因为往里走，代表宽度减小，那么宽度小的时候，只有遇上更高的高度才能组成更加大的container。

int maxArea(vector<int> &height) 
    {
	    int area = 0;
	    int i = 0, j = height.size()-1;
	    while (i<j)
	    {
		    area = max(area, (j-i)*min(height[i], height[j]));
		    (height[i] > height[j])? j--:i++;
	    }
	    return area;
    }