HDU1228：A + B

Problem Description

读入两个小于100的正整数A和B,计算A+B.
需要注意的是:A和B的每一位数字由对应的英文单词给出.

Input

测试输入包含若干测试用例,每个测试用例占一行,格式为"A + B =",相邻两字符串有一个空格间隔.当A和B同时为0时输入结束,相应的结果不要输出.

Output

对每个测试用例输出1行,即A+B的值.

Sample Input

one + two = three four + five six = zero seven + eight nine = zero + zero =

Sample Output

3 90 96

#include <iostream>
#include <cstdio>
#include <string.h>
using namespace std;

char num[10][10] = {"zero","one","two","three","four","five","six","seven","eight","nine"};

int search(char ch[])
{
    int i;
    for(i = 0;i<10;i++)
    {
        if(!strcmp(ch,num[i]))
        break;
    }
    return i;
}

int main()
{
    char count[10];
    int a,b;

    while(1)
    {
        a = 0;
        while(scanf("%s",count) && strcmp(count,"+"))
        {
            a = a*10+search(count);
        }
        b = 0;
        while(scanf("%s",count) && strcmp(count,"="))
        {
            b = b*10+search(count);
        }
        if(a == 0 && b == 0)
        return 0;
        else
        cout << a+b << endl;
    }

    return 0;
}