任给1个十进制的数字，输出该数字转化为二进制后1的个数

任给1个十进制的数字，输出该数字转化为二进制后1的个数

1. 方法1

public static int Method(int number)

{

int i = 1;

while ((number & (number - 1)) != 0)

{

number = (number & (number - 1));

i++;

}

return i;

}

2. 方法2

public static int Method2(int number)

{

int i = 1;

while (number!=1)

{

if (number % 2 == 1)

{

i++;

number -= 1;

}

number = number/2;

}

return i;

}