一个Socket服务的例子! 请高手指点无法捕捉的输出如何修改?

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　　一个Socket服务的例子!
　　请高手指点无法捕捉的输出如何修改?
　　//服务端
　　package org.dyol.net;
　　import java.net.*;
　　import java.io.*;
　　import java.util.*;
　　public class Console {
　　
　　public static void main(String args[]){
　　if (args.length!=1)
　　throw new IllegalArgumentException("unlawful number of args:\nUSER:\n\tConsole \n");
　　new Console(Integer.parseInt(args[0]));
　　}
　　
　　public Console(int port){
　　this.port = port;
　　try {
　　ServerSocket socket = new ServerSocket(port);
　　System.out.println("Start service on "+port);
　　while(true){
　　new Transmit(socket.accept()).start();
　　}
　　}catch (IOException e){}
　　}
　　
　　private class Transmit extends Thread {
　　private String sys = System.getProperty("os.name")+" "+System.getProperty("os.arch")+" "+System.getProperty("os.version");
　　private Socket sock;
　　public Transmit(Socket sock){
　　this.sock = sock;
　　try {
　　input = new BufferedReader(new InputStreamReader(sock.getInputStream(),"gb2312"));
　　output = new PrintStream(sock.getOutputStream());
　　output.println(sys);
　　}catch(Exception e){}
　　}
　　public void run(){
　　System.out.println("");
　　}
　　}
　　
　　private int port = 520;
　　private BufferedReader input;
　　private PrintStream output;
　　private String cmd;
　　private Process proc;
　　private String msg;
　　private BufferedReader dis ;
　　
　　}
　　//客户端
　　import java.io.*;
　　import java.net.*;
　　public class Client {
　　public static void main(String[] args){
　　if (args.length != 2)
　　throw new IllegalArgumentException("Wrong number of args");
　　String host = args[0];
　　int port = Integer.parseInt(args[1]);
　　new Client(host, port);
　　}
　　public Client(String host,int port){
　　try {
　　Socket s = new Socket(host, port);
　　final BufferedReader echo=new BufferedReader(new InputStreamReader(s.getInputStream(),"gb2312"));
　　PrintWriter ps = new PrintWriter(s.getOutputStream());
　　BufferedReader cmd = new BufferedReader(new InputStreamReader(System.in,"gb2312"));
　　final PrintWriter pis = new PrintWriter(System.out, true);
　　pis.println("Connected to "+s.getInetAddress()+":" + s.getPort());
　　Thread t = new Thread() {
　　public void run() {
　　char[] buffer = new char[1024];
　　int ch;
　　try {
　　while((ch = echo.read(buffer)) != -1) {
　　for(int i = 0; i <ch i>　　if (buffer[i] == '\n') pis.println(); <br>　　else pis.print(buffer[i]); <br>　　} <br>　　pis.flush(); <br>　　} <br>　　}catch (IOException e){ <br>　　pis.println(e); <br>　　} <br>　　pis.println("Connection closed by server."); <br>　　System.exit(0); <br>　　} <br>　　}; <br>　　t.setPriority(Thread.currentThread().getPriority() + 1); <br>　　t.start(); <br>　　String line; <br>　　while((line = cmd.readLine()) != null) { <br>　　ps.print(line + "\n"); <br>　　ps.flush(); <br>　　} <br>　　s.close(); <br>　　pis.println("Connection closed by client."); <br>　　System.exit(0); <br>　　}catch (Exception e) {} <br>　　} <br>　　} <br>　　 <br>　　一个Socket服务的例子! 请高手指点无法捕捉的输出如何修改? //服务端 package org.dyol.net; import java.net.*; import java.io.*; import java.util.*; public class Console { public static void main(String args[]){ if (args.length!=1) throw new IllegalArgumentException("unlawful number of args:\nUSER:\n\tConsole \n"); new Console(Integer.parseInt(args[0])); } public Console(int port){ this.port = port; try { ServerSocket socket = new ServerSocket(port); System.out.println("Start service on "+port); while(true){ new Transmit(socket.accept()).start(); } }catch (IOException e){} } private class Transmit extends Thread { private String sys = System.getProperty("os.name")+" "+System.getProperty("os.arch")+" "+System.getProperty("os.version"); private Socket sock; public Transmit(Socket sock){ this.sock = sock; try { input = new BufferedReader(new InputStreamReader(sock.getInputStream(),"gb2312")); output = new PrintStream(sock.getOutputStream()); output.println(sys); }catch(Exception e){} } public void run(){ System.out.println(""); } } private int port = 520; private BufferedReader input; private PrintStream output; private String cmd; private Process proc; private String msg; private BufferedReader dis ;} //客户端 import java.io.*; import java.net.*; public class Client { public static void main(String[] args){ if (args.length != 2) throw new IllegalArgumentException("Wrong number of args"); String host = args[0]; int port = Integer.parseInt(args[1]); new Client(host, port); } public Client(String host,int port){ try { Socket s = new Socket(host, port); final BufferedReader echo=new BufferedReader(new InputStreamReader(s.getInputStream(),"gb2312")); PrintWriter ps = new PrintWriter(s.getOutputStream()); BufferedReader cmd = new BufferedReader(new InputStreamReader(System.in,"gb2312")); final PrintWriter pis = new PrintWriter(System.out, true); pis.println("Connected to "+s.getInetAddress()+":" + s.getPort()); Thread t = new Thread() { public void run() { char[] buffer = new char[1024]; int ch; try { while((ch = echo.read(buffer)) != -1) { for(int i = 0; i <ch e i system.exit client. by closed pis.println s.close ps.flush ps.print while line string t.start t.setpriority server. pis.flush pis.print else if><br>本文转自 <br><a href="http://www.cn-java.com/www1/?action-viewnews-itemid-2717">http://www.cn-java.com/www1/?action-viewnews-itemid-2717</a></ch></ch>