PAT 1001. A+B Format (20)

原创于 2012-03-12 10:22:30 发布 · 137 阅读

0 ·

CC 4.0 BY-SA版权

PAT 专栏收录该内容

8 篇文章

订阅专栏

本博客介绍了一个简单的程序，用于计算两个整数的和，并将结果以标准格式输出，即数字分组为三位一断，用逗号分隔。程序通过读取输入文件中的整数对，计算它们的和，然后根据大小调整输出格式。

Calculate a + b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

Input

Each input file contains one test case. Each case contains a pair of integers a and b where -1000000 <= a, b <= 1000000. The numbers are separated by a space.

Output

For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.

Sample Input

-1000000 9

Sample Output

-999,991

#include<stdio.h>
int main()
{
  int a,b;
  int sum;
  while(scanf("%d%d\n",&a,&b) != EOF){
        sum = a+b;
	if(sum < 0){
	printf("-");
	sum = -sum;
	}
    if(sum>=1000000){
        printf("%d,%03d,%03d\n",sum/1000000, (sum/1000)%1000, sum%1000);
    }
    else if(sum >= 1000){
        printf("%d,%03d\n",sum/1000,sum%1000);
    } else{
        printf("%d\n", sum);
    }
  }
  return 0;
}