CREATE TABLE cj641(
rank MEDIUMINT(8),
zkzh VARCHAR(10),
kmmc VARCHAR(10),
kmdm VARCHAR(10),
cj INT(10)
) SELECT rank,zkzh,kmmc,kmdm,cj FROM cjrank WHERE kmdm='641';
create table rcj641(id mediumint(8) auto_increment primary key,cj INT(10)) select cj from cj641 group by cj order by cj DESC;
UPDATE cj641 SET cj641.rank = (SELECT rcj641.id FROM rcj641 WHERE cj641.cj = rcj641.cj);
CREATE TABLE cj642(
rank MEDIUMINT(8),
zkzh VARCHAR(10),
kmmc VARCHAR(10),
kmdm VARCHAR(10),
cj INT(10)
) SELECT rank,zkzh,kmmc,kmdm,cj FROM cjrank WHERE kmdm='642';
create table rcj642(id mediumint(8) auto_increment primary key,cj INT(10)) select cj from cj642 group by cj order by cj DESC;
UPDATE cj642 SET cj642.rank = (SELECT rcj642.id FROM rcj642 WHERE cj642.cj = rcj642.cj);
成绩归类,排名
最新推荐文章于 2025-11-01 19:53:35 发布
本文介绍了一种使用SQL创建表格并进行数据处理的方法,通过从源表cjrank中选择特定科目代码的数据,创建新的表格cj641和cj642,并基于这些表格创建了排名表rcj641和rcj642。最后,更新了cj641和cj642表中的排名字段,使其与排名表中的ID相对应。
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