自悟

无法做到对自我的要求这是一个人一生最大的悲哀。
---------2013 Write
// @author fkxr(luogu uid = 995934) // https://hydro.ac/d/Fkxr/p/IO // CC BY-SA 4.0 https://creativecommons.org/licenses/by-sa/4.0/ #include <bits/stdc++.h> #define endl cerr<<"------------------I Love the Olympiad in Informatics------------------\n"; #define int long long #define _CRT_SECURE_NO_WARNINGS 1 #define _4x _4x #define all(x) x.begin(),x.end() //#define BIT BIT //#define ST ST #define dsu dsu using namespace std; #ifdef __linux__ #define gc getchar_unlocked #define pc putchar_unlocked #else #define gc getchar #define pc putchar #endif #define ds(x) (x=='\r'||x=='\n'||x==' ') #define MAX 20 namespace fastIO {//吾常于「oi-wiki」习,自「快读快写」之术。 template<typename T>inline void r(T& a) { a = 0; char ch = gc(); bool ok = 0; for (; ch < '0' || ch>'9';)ok ^= (ch == '-'), ch = gc(); for (; ch >= '0' && ch <= '9';)a = (a << 1) + (a << 3) + (ch ^ 48), ch = gc(); if (ok)a = -a; } template<typename T>inline void w(T a) { if (a == 0) { pc('0'); return; }static char ch[MAX]; int till = 0; if (a < 0) { pc('-'); for (; a;)ch[till++] = -(a % 10), a /= 10; } else for (; a;)ch[till++] = a % 10, a /= 10; for (; till;)pc(ch[--till] ^ 48); } struct FIstream { inline FIstream operator>>(int& a) { r(a); return{}; } inline FIstream operator>>(char& ch) { ch = gc(); for (; ds(ch);)ch = gc(); return{}; } inline FIstream operator>>(string& s) { s = ""; char ch = gc(); for (; ds(ch);)ch = gc(); for (; !(ds(ch) || ch == EOF);) { s.push_back(ch); ch = gc(); }return{}; } template<typename T>inline FIstream operator<<(T& a) { r(a); return{}; } inline void is(int n, string& s) { s = ""; char ch = gc(); for (; ds(ch);)ch = gc(); for (; n--;) { s.push_back(ch); ch = gc(); } } }in; struct FOstream { inline FOstream operator<<(const int a) { w(a); return{}; } inline FOstream operator<<(const char ch) { pc(ch); return{}; } inline FOstream operator<<(const string s) { for (int i = 0; i < s.size(); i++)pc(s[i]); return{}; } template<typename T>inline FOstream operator>>(const T a) { w(a); return{}; } }out; }using fastIO::in; using fastIO::out; #undef ds #define eout cerr namespace Maths {//吾常赴「MO」之赛,自「数学」之术。 const bool __is_P[] = { 0,0,1,1,0,1,0,1,0,0,0,1,0,1,0,0,0,1,0,1,0,0,0,1,0,0,0,0,0,1 }; inline bool IP1(const int a) { if (a <= 29)return __is_P[a]; if (a % 2 == 0 || a % 3 == 0 || a % 5 == 0)return 0; for (int i = 6;; i += 6) { if (((i + 1) * (i + 1)) > a)return 1; if (a % (i + 1) == 0)return 0; if (((i + 5) * (i + 5)) > a)return 1; if (a % (i + 5) == 0)return 0; } } #define times(a,b,m) (c=(unsigned long long)a*b-(unsigned long long)((long double)a/m*b+0.5L)*m,c<m?c:m+c) inline int power(int a, int b, const int mod = -1) { unsigned long long c; int ans = 1; if (mod == -1) { for (; b;) { if (b & 1)ans *= a; b >>= 1; a *= a; }return ans; }for (; b;) { if (b & 1)ans = times(ans, a, mod); b >>= 1; a = times(a, a, mod); }return ans; } const int Suk[] = { 2,325,9375,28178,450775,9780504,1795265022 }; inline bool chk(const int n, int a, int b, int x) { if (x >= n) return 1; unsigned long long c; int v = power(x, a, n); if (v == 1)return 1; int j = 1; while (j <= b) { if (v == n - 1)break; v = times(v, v, n); j++; }if (j > b)return 0; return 1; } inline bool IP(int n) { if (n < 3 || n % 2 == 0)return n == 2; if (n <= 1e6) { return IP1(n); } else { int a = n - 1, b = 0; while (a % 2 == 0)a >>= 1, b++; for (int k : Suk)if (!chk(n, a, b, k))return 0; return 1; } } #undef times } using Maths::power; using Maths::IP; namespace exs { #ifdef _4x int dx[] = { 1,-1,0,0 }, dy[] = { 0,0,1,-1 }; #else int dx[] = { 1,0,-1,-1,1,1,0,-1 }, dy[] = { 1,1,1,0,0,-1,-1,-1 }; #endif template<typename T, typename T1, typename T2>inline bool rg(T l, T1 r, T2 x) { return l <= x && x <= r; } inline bool emc(const int& a, const int& b) { return a > b; } #ifndef _MSC_VER void Freopen(string s) { freopen((s + ".in").c_str(), "r", stdin); freopen((s + ".out").c_str(), "w", stdout); } #endif #ifdef BIT//吾常读「《算法竞赛进阶指南》」之书,自「树状数组」之术。 struct bit { vector<int> c0, c1; int n; inline void Add(vector<int>& c, int p, int v) { for (; p <= n; p += p & -p) c[p] += v; } inline int Sum(const vector<int>& c, int p) { int t = 0; for (; p; p -= p & -p) t += c[p]; return t; } inline int sum(int l, int r) { assert(n != 0); return Sum(c0, r) * r - Sum(c1, r) - Sum(c0, l - 1) * (l - 1) + Sum(c1, l - 1); } inline void add(int l, int r, int v) { assert(n != 0); Add(c0, l, v); Add(c0, r + 1, -v); Add(c1, l, (l - 1) * v); Add(c1, r + 1, -r * v); } inline void init(const vector<int>& c) { n = c.size() - 1; c0.resize(n + 2); c1.resize(n + 2); int last = 0; for (int i = 1; i <= n; i++) { last = c[i] - last; Add(c0, i, last); Add(c1, i, last * (i - 1)); last = c[i]; } } }; #endif #ifdef ST//吾常读「《算法竞赛进阶指南》」之书,自「ST表」之术。 struct st { vector<int> lg; vector<vector<int>> f; inline void init(const vector<int>& c) { int len = c.size() - 1; lg.resize(len + 2); for (int i = 2; i <= len; i++) lg[i] = lg[i >> 1] + 1; f.resize(18, vector<int>(len + 2)); for (int i = 1; i <= len; i++) f[0][i] = c[i]; for (int j = 1; (1 << j) <= len; j++) for (int i = 1; i + (1 << j) - 1 <= len; i++) f[j][i] = max(f[j - 1][i], f[j - 1][i + (1 << (j - 1))]); } inline int q(int l, int r) { int j = lg[r - l + 1]; return max(f[j][l], f[j][r - (1 << j) + 1]); } }; #endif #ifdef dsu//0x 吾常读「《算法竞赛进阶指南》」之书,自「并查集」之术。 struct dsu { vector<int> fa, size; dsu(int size_) :fa(size_), size(size_, 1) { iota(fa.begin(), fa.end(), 0); } inline int find(int x) { return fa[x] == x ? x : fa[x] = find(fa[x]); } inline void unite(int x, int y) { x = find(x), y = find(y); if (x == y)return; if (size[x] < size[y])swap(x, y); fa[y] = x; size[x] += size[y]; } }; #endif }using namespace exs; int d[]={6,2,5,5,4,5,6,3,7,6}; int f(int x){ int ans=0; for(;x;x/=10){ ans+=d[x%10]; } return ans; } void Main() { int l,r;in>>l>>r; if(r-l>50){ out<<"2\n"; }else{ for(int i=l;i<r;i++){ if(f(i)==f(i+1)){ out<<"2\n"; return ; } } out<<"1\n"; } } signed main() { Main(); return 0; }
10-15
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