memcpy 函数学习

还是英文来的的更加直接些。

Copy block of memory

Copies the values of num bytes from the location pointed by source directly to the memory block pointed by destination.

The underlying type of the objects pointed by both the source and destination pointers are irrelevant for this function; The result is a binary copy of the data.

The function does not check for any terminating null character in source - it always copies exactly num bytes.

To avoid overflows, the size of the arrays pointed by both the destination and source parameters, shall be at least num bytes, and should not overlap (for overlapping memory blocks, memmove is a safer approach).

函数存数据的形式是二进制的，并且是精确长度的，没有终止符，为了防止内存溢出，通常都指定精确大小的。

Parameters

destination

Pointer to the destination array where the content is to be copied, type-casted to a pointer of type void*.

source

Pointer to the source of data to be copied, type-casted to a pointer of type void*.

num

Number of bytes to copy.

/* memcpy example */ #include <stdio.h> #include <string.h> int main () { char str1[]="Sample string"; char str2[40]; char str3[40]; memcpy (str2,str1,strlen(str1)+1); memcpy (str3,"copy successful",16); printf ("str1: %s\nstr2: %s\nstr3: %s\n",str1,str2,str3); return 0; }

结果
str1: Sample stringstr2: Sample stringstr3: copy successful