解决: div的 onclike ( this ) 得到选择
由 window.event 得到 鼠标 x y
由 this.style.top/left 改变 div 位置
var x,y;
function mousedown(obj)
{
obj.onmousemove = mousemove;
obj.onmouseup = mouseup;
oEvent = window.event ? window.event : event;
x = oEvent.clientX;
y = oEvent.clientY;
}
function mousemove()
{
oEvent = window.event ? window.event : event;
var _top = oEvent.clientY - y + parseInt(this.style.top) + "px"; // oEvent.clientY - y 为div 上 移动的位置 再反映到 //parseInt(this.style.top)
var _left = oEvent.clientX - x + parseInt(this.style.left) +"px";
this.style.top = _top;
this.style.left = _left;
x = oEvent.clientX;
y = oEvent.clientY
}
function mouseup()
{
this.onmousemove = null;
this.onmouseup = null;
}
由 window.event 得到 鼠标 x y
由 this.style.top/left 改变 div 位置
var x,y;
function mousedown(obj)
{
obj.onmousemove = mousemove;
obj.onmouseup = mouseup;
oEvent = window.event ? window.event : event;
x = oEvent.clientX;
y = oEvent.clientY;
}
function mousemove()
{
oEvent = window.event ? window.event : event;
var _top = oEvent.clientY - y + parseInt(this.style.top) + "px"; // oEvent.clientY - y 为div 上 移动的位置 再反映到 //parseInt(this.style.top)
var _left = oEvent.clientX - x + parseInt(this.style.left) +"px";
this.style.top = _top;
this.style.left = _left;
x = oEvent.clientX;
y = oEvent.clientY
}
function mouseup()
{
this.onmousemove = null;
this.onmouseup = null;
}
本文介绍了一种使用JavaScript实现拖拽效果的方法。通过监听鼠标按下、移动及释放等事件,可以实时更新元素的位置,使得div元素能够跟随鼠标进行移动。
670

被折叠的 条评论
为什么被折叠?



