Description
Ugly numbers are numbers whose only prime factors are 2, 3 or 5. The sequence
1, 2, 3, 4, 5, 6, 8, 9, 10, 12, ...
shows the first 10 ugly numbers. By convention, 1 is included.
Given the integer n,write a program to find and print the n'th ugly number.
1, 2, 3, 4, 5, 6, 8, 9, 10, 12, ...
shows the first 10 ugly numbers. By convention, 1 is included.
Given the integer n,write a program to find and print the n'th ugly number.
Input
Each line of the input contains a postisive integer n (n <= 1500).Input is terminated by a line with n=0.
Output
For each line, output the n’th ugly number .:Don’t deal with the line with n=0.
Sample Input
1 2 9 0
Sample Output
1 2 10
#include<stdio.h>
int ugly[1505];
int min(int a,int b)
{
return a>b?b:a;
}
int main()
{
int p2,p3,p5;
int i,in;
p2=0,p3=0,p5=0;
ugly[0]=1;
for(i=1;i<1500;i++)
{
ugly[i]=min(min(ugly[p2]*2,ugly[p3]*3),ugly[p5]*5);
if(ugly[i]==ugly[p2]*2) p2++;
if(ugly[i]==ugly[p3]*3) p3++;
if(ugly[i]==ugly[p5]*5) p5++;
}
//printf("%d %d %d",p2,p3,p5);
while(scanf("%d",&in)&&in!=0)
{
printf("%d/n",ugly[in-1]);
}
return 0;
}

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