Java向服务器发送POST请求

最新推荐文章于 2024-02-25 19:48:48 发布

iteye_12668

最新推荐文章于 2024-02-25 19:48:48 发布

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分类专栏： Java 文章标签： Java HTML

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本文介绍了一个Java客户端向服务器发送数据并接收响应的示例。通过HTTP协议实现，客户端使用BufferedWriter发送字符串数据到指定服务器路径，并通过BufferedReader读取服务器返回的信息。

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public String sendToServer(String content) {
String urlPath = "http://127.0.0.1:8080/sunrise/test.do"; //服务器地址
StringBuffer sbf = new StringBuffer();
BufferedWriter writer = null;
BufferedReader reader = null;
HttpURLConnection uc = null;
try {
URL url = new URL(urlPath);
uc = (HttpURLConnection)url.openConnection();
uc.setDoOutput(true);
writer = new BufferedWriter(
new OutputStreamWriter(uc.getOutputStream())); //向服务器传送数据
writer.write(content); //传送的数据
writer.flush();
writer.close();
reader = new BufferedReader(
new InputStreamReader(uc.getInputStream()));//读取服务器响应信息
String line;
while ((line = reader.readLine()) != null){
sbf.append(line);
}
reader.close();
uc.disconnect();
} catch (Exception e) {
sbf.append("服务器连接失败！请稍后重新操作");
} finally{
closeIO(writer,reader); //关闭流
}
return sbf.toString().trim();
}

/**
* 关闭流
*/
private void closeIO(BufferedWriter writer,BufferedReader reader){
if (writer != null) {
try {
writer.close();
writer = null;
} catch (Exception e) {

}
}
if (reader != null) {
try {
reader.close();
reader = null;
} catch (Exception e) {

}
}
}
/**
* 服务器端代码
* 不要使用request.getParameter();因为该方法和
* request.getReader();和request.getInputStream();
* 方法冲突。
*/
@Override
protected void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
response.setContentType("text/html");//注意加上
BufferedReader reader = null;
try {
reader = request.getReader();//获得字符流
StringBuffer content= new StringBuffer();
String line;
while ((line = reader.readLine()) != null){
content.append(line+"\r\n");
}
System.out.println(content.toString());
} catch (Exception e) {

}finally{
try {
reader.close();
reader = null;
} catch (Exception e) {

}
}
}