/*--原帖地址:
http://community.youkuaiyun.com/Expert/topic/3841/3841808.xml?temp=.4308588
--*/
--测试数据
create table tb(year int,month int,No varchar(10),Name varchar(10),部门 varchar(10),工资 int)
insert tb select 2004,10,'A001','AAA','DDD',1000
union all select 2004,10,'B001','BBB','DDD',800
union all select 2004,11,'A001','AAA','DDD',1100
union all select 2004,11,'B001','BBB','DDD',1000
union all select 2004,12,'A001','AAA','DDD',1200
union all select 2004,12,'B001','BBB','DDD',1050
/*--处理要求
将月份做为字段,并且反应逐月的工资增幅,例如上面的数据要求结果如下,注意最小的年月是没有增幅的
No Name 部门 2004_10 2004_11 2004_11增幅 2004_12 2004_12增幅
------ ------ ------ --------- -------- ----------- --------- ------------
A001 AAA DDD 1000 1100 10.00% 1200 9.09%
B001 BBB DDD 800 1000 25.00% 1050 5.00%
--*/
go
--查询处理
declare @s nvarchar(4000),@i int
select @s='',@i=0
select @s=@s+','+quotename(fd)
+'=sum(case when a.year='+year
+' and a.month='+month
+' then a.工资 end)'
+case @i when 0 then ''
else ','+quotename(fd+'增幅')
+'=cast(cast(sum(case when a.year='+year
+' and a.month='+month
+' then a.工资-b.工资 end)*100.'
+'/sum(case when a.year='+year
+' and a.month='+month
+' then b.工资 end)'
+' as decimal(10,2)) as varchar)+''%'''
end,@i=@i+1
from(
select year=rtrim(year),month=rtrim(month),
fd=rtrim(year)+'_'+rtrim(month)
from tb group by year,month)a
exec('select a.No,a.Name,a.部门'+@s+'
from tb a
left join tb b on a.No=b.No and a.Name=b.Name and a.部门=b.部门
and a.year=b.year+(b.month)/12
and a.month=b.month%12+1
group by a.No,a.Name,a.部门')
go
--删除测试
drop table tb
博客展示了一段SQL代码,用于处理工资数据。先创建测试表并插入数据,要求将月份作为字段,计算并展示逐月工资增幅。随后通过动态SQL查询处理数据,最后删除测试表,实现了对工资数据的特定处理需求。
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