java 判断ip是否属于一个网段

IP地址验证与范围检查

最新推荐文章于 2023-02-14 22:30:09 发布

原创最新推荐文章于 2023-02-14 22:30:09 发布 · 892 阅读

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本文介绍了一个Java方法，用于验证一个IP地址是否位于指定的IP范围内。通过正则表达式确保输入格式正确，并将IP地址转换为长整型数值进行比较。此方法适用于网络安全、网络管理等场景。

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public class ipTest {
    /**
     * 判断IP是否在指定范围；
     */

    public static boolean ipIsValid(String ipSection, String ip) {
        if (ipSection == null)
            throw new NullPointerException("IP段不能为空！");
        if (ip == null)
            throw new NullPointerException("IP不能为空！");
        ipSection = ipSection.trim();
        ip = ip.trim();
        final String REGX_IP = "((25[0-5]|2[0-4]\\d|1\\d{2}|[1-9]\\d|\\d)\\.){3}(25[0-5]|2[0-4]\\d|1\\d{2}|[1-9]\\d|\\d)";
        final String REGX_IPB = REGX_IP + "\\-" + REGX_IP;
        if (!ipSection.matches(REGX_IPB) || !ip.matches(REGX_IP))
            return false;
        int idx = ipSection.indexOf('-');
        String[] sips = ipSection.substring(0, idx).split("\\.");
        String[] sipe = ipSection.substring(idx + 1).split("\\.");
        String[] sipt = ip.split("\\.");
        long ips = 0L, ipe = 0L, ipt = 0L;
        for (int i = 0; i < 4; ++i) {
            ips = ips << 8 | Integer.parseInt(sips[i]);
            ipe = ipe << 8 | Integer.parseInt(sipe[i]);
            ipt = ipt << 8 | Integer.parseInt(sipt[i]);
        }
        if (ips > ipe) {
            long t = ips;
            ips = ipe;
            ipe = t;
        }
        return ips <= ipt && ipt <= ipe;
    }
    public static void main(String[] args) {
        if (ipIsValid("192.168.1.1-192.168.1.10", "192.168.3.54")) {
            System.out.println("ip属于该网段");
        } else
            System.out.println("ip不属于该网段");
    }
}

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