usaco_beads

本文介绍了一个使用C++解决的珠串问题算法。该算法通过读取输入文件中的珠子颜色序列,并在此基础上计算出能获得的最大数量珠子的方法。文章详细展示了如何处理颜色变化及白色珠子的特殊规则。

摘要生成于 C知道 ,由 DeepSeek-R1 满血版支持, 前往体验 >

/* ID:mingcha1 PROG: beads LANG: C++ */ #include<iostream> #include<string> #include<fstream> using namespace std; ofstream fout ("beads.out"); ifstream fin ("beads.in"); const int SIZE=1000; struct node{ int len,pos; }a[SIZE]; int main(){ string str; int n; fin>>n>>str; str+=str; char cur=str[0]; int num=0; a[num].pos=0; for(int i=1;str[i];++i){ if(cur!=str[i] && str[i]!='w'){ a[num].len=i-a[num].pos; a[++num].pos=i; cur=str[i]; } } a[num].len=n*2-a[num].pos; //fout<<str<<endl; //for(int i=0;i<=num;++i){ // fout<<a[i].len<<endl; //} for(int i=1;i<=num;++i){ for(int j=a[i].pos-1; j>=0 &&str[j]=='w';--j){ a[i].len++; if(a[i].len>n) a[i].len=n; } }//modify /*fout<<"asdf/n"; for(int i=0;i<=num;++i){ fout<<a[i].len<<endl; }*/ int max=-1,pos=0,flag=0; for(int i=0;i<=num;++i){ if(a[i].len+a[i+1].len>=max){ if(a[i].len+a[i+1].len==max){ if(str[a[i+1].pos-1]!='w'){ pos=a[i+1].pos; } } else{ max=a[i].len+a[i+1].len; pos=a[i+1].pos; } } } /*cout<<"===="<<endl; cout<<pos<<endl;*/ for(int i=pos-1;i>=0 &&str[i]=='w';--i) flag++; if(num!=0){ if(max-flag<=n) fout<<max-flag<<endl; else fout<<n<<endl; } else{ if(a[0].len<=n) fout<<a[0].len<<endl; else fout<<n<<endl; } } //333 //rwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwbrwb

评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值