Day:
ddnumber12
dyabbreviatedfri
dayspelledoutfriday
ddspthspelledout,ordinaltwelfth
Month:
mmnumber03
monabbreviatedmar
monthspelledoutmarch
Year:
yytwodigits98
yyyyfourdigits1998
24小时格式下时间范围为:0:00:00-23:59:59....
12小时格式下时间范围为:1:00:00-12:59:59....
1.日期和字符转换函数用法(to_date,to_char)
2.selectto_char(to_date(222,'J'),'Jsp')fromdual
显示TwoHundredTwenty-Two
3.求某天是星期几selectto_char(to_date('2002-08-26','yyyy-mm-dd'),'day')fromdual;
星期一
selectto_char(to_date('2002-08-26','yyyy-mm-dd'),'day','NLS_DATE_LANGUAGE=American')fromdual;
monday
设置日期语言ALTERSESSIONSETNLS_DATE_LANGUAGE='AMERICAN';
也可以这样TO_DATE('2002-08-26','YYYY-mm-dd','NLS_DATE_LANGUAGE=American')
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4.两个日期间的天数selectfloor(sysdate-to_date('20020405','yyyymmdd'))fromdual;
5.时间为null的用法selectid,active_datefromtable1
UNION
select1,TO_DATE(null)fromdual;
注意要用TO_DATE(null)
6.a_datebetweento_date('20011201','yyyymmdd')andto_date('20011231','yyyymmdd')
那么12月31号中午12点之后和12月1号的12点之前是不包含在这个范围之内的。
所以,当时间需要精确的时候,觉得to_char还是必要的
7.日期格式冲突问题
输入的格式要看你安装的ORACLE字符集的类型,比如:US7ASCII,date格式的类型就是:'01-Jan-01'
altersystemsetNLS_DATE_LANGUAGE=American
altersessionsetNLS_DATE_LANGUAGE=American
或者在to_date中写selectto_char(to_date('2002-08-26','yyyy-mm-dd'),'day','NLS_DATE_LANGUAGE=American')fromdual;
注意我这只是举了NLS_DATE_LANGUAGE,当然还有很多,
可查看select*fromnls_session_parameters
select*fromV$NLS_PARAMETERS
8.selectcount(*)
from(selectrownum-1rnum
fromall_objects
whererownum<=to_date('2002-02-28','yyyy-mm-dd')-to_date('2002-
02-01','yyyy-mm-dd')+1
)
whereto_char(to_date('2002-02-01','yyyy-mm-dd')+rnum-1,'D')
not
in('1','7')
查找2002-02-28至2002-02-01间除星期一和七的天数
在前后分别调用DBMS_UTILITY.GET_TIME,让后将结果相减(得到的是1/100秒,而不是毫秒).
selectmonths_between(to_date('01-31-1999','MM-DD-YYYY'),
to_date('12-31-1998','MM-DD-YYYY'))"MONTHS"FROMDUAL;
1
selectmonths_between(to_date('02-01-1999','MM-DD-YYYY'),
to_date('12-31-1998','MM-DD-YYYY'))"MONTHS"FROMDUAL;
1.03225806451613
10.Next_day的用法Next_day(date,day)
Monday-Sunday,forformatcodeDAY
Mon-Sun,forformatcodeDY
1-7,forformatcodeD
11.selectto_char(sysdate,'hh:mi:ss')TIMEfromall_objects
注意:第一条记录的TIME与最后一行是一样的
可以建立一个函数来处理这个问题createorreplacefunctionsys_datereturndateis
begin
returnsysdate;
end;
selectto_char(sys_date,'hh:mi:ss')fromall_objects;
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12.获得小时数SELECTEXTRACT(HOURFROMTIMESTAMP'2001-02-162:38:40')fromoffer
SQL>selectsysdate,to_char(sysdate,'hh')fromdual;
SYSDATETO_CHAR(SYSDATE,'HH')
-----------------------------------------
2003-10-1319:35:2107
SQL>selectsysdate,to_char(sysdate,'hh24')fromdual;
SYSDATETO_CHAR(SYSDATE,'HH24')
-------------------------------------------
2003-10-1319:35:2119
获取年月日与此类似
13.年月日的处理selectolder_date,
newer_date,
years,
months,
abs(
trunc(
newer_date-
add_months(older_date,years*12+months)
)
)days
from(select
trunc(months_between(newer_date,older_date)/12)YEARS,
mod(trunc(months_between(newer_date,older_date)),
12)MONTHS,
newer_date,
older_date
from(selecthiredateolder_date,
add_months(hiredate,rownum)+rownumnewer_date
fromemp)
)
14.处理月份天数不定的办法selectto_char(add_months(last_day(sysdate)+1,-2),'yyyymmdd'),last_day(sysdate)fromdual
15.找出今年的天数selectadd_months(trunc(sysdate,'year'),12)-trunc(sysdate,'year')fromdual
闰年的处理方法to_char(last_day(to_date('02'||:year,'mmyyyy')),'dd')