Javascript错误处理之抛出自定义错误

最新推荐文章于 2025-01-21 10:03:32 发布

原创最新推荐文章于 2025-01-21 10:03:32 发布 · 365 阅读

1 ·

CC 4.0 BY-SA版权

文章标签：

#JavaScript #ViewUI

JavaScript 专栏收录该内容

28 篇文章

订阅专栏

本文介绍了一种使用JavaScript实现自定义异常的方法，并通过两个示例函数演示了如何进行参数验证及错误处理。通过这种方式可以确保代码的健壮性和易维护性。

//抛出自定义异常
function divide1 (iNum1, iNum2) {
    try{
        if(arguments.length != 2) {
            throw new Error("divide() requires two arguments.");
        } else if (typeof(iNum1) != "number" || typeof(iNum2) != "number") {
            throw new Error("divide() requires two numbers for arguments.");
        }
        return iNum1.valueOf() / iNum2.valueOf();
    } catch (e) {
        alert(e.message);
        return -1;
    }
}

//模拟assert
function assert(bCondition, sErrorMessage){
    if(bCondition) {
        throw new Error(sErrorMessage);
    }
}

function divide2 (iNum1, iNum2) {
    try{
        assert(arguments.length != 2, "divide() requires two arguments.");
        assert(typeof(iNum1) != "number" || typeof(iNum2) != "number", "divide() requires two numbers for arguments.");
        assert(iNum2.valueOf() == 0, "divisor can not be zero.");
        return iNum1.valueOf() / iNum2.valueOf();
    } catch (e) {
        alert(e.message);
        return -1;
    }
}
window.onload=function(){
    divide1("a","a");
    divide2(2,0);
}
//抛出自定义异常
function divide1 (iNum1, iNum2) {
    try{
        if(arguments.length != 2) {
            throw new Error("divide() requires two arguments.");
        } else if (typeof(iNum1) != "number" || typeof(iNum2) != "number") {
            throw new Error("divide() requires two numbers for arguments.");
        }
        return iNum1.valueOf() / iNum2.valueOf();
    } catch (e) {
        alert(e.message);
        return -1;
    }
}

//模拟assert
function assert(bCondition, sErrorMessage){
    if(bCondition) {
        throw new Error(sErrorMessage);
    }
}

function divide2 (iNum1, iNum2) {
    try{
        assert(arguments.length != 2, "divide() requires two arguments.");
        assert(typeof(iNum1) != "number" || typeof(iNum2) != "number", "divide() requires two numbers for arguments.");
        assert(iNum2.valueOf() == 0, "divisor can not be zero.");
        return iNum1.valueOf() / iNum2.valueOf();
    } catch (e) {
        alert(e.message);
        return -1;
    }
}
window.onload=function(){
    divide1("a","a");
    divide2(2,0);
}