java 验证ldap的用户

这几天做基于ibm portal 6的登录改造， 验证是基于ldap的。

由于没有登录portlet的源代码，于是就自己去做这个ldap的用户认证。一开始向到根据用户名和密码去查找ldap，根据找不着得到用户来决定验证是否成功， 但这个密码无论怎样都验证不成功。。。只好放弃该方法

难道就没有办法验证ldap用户了？？网上搜索， 还是得到了方法， 其实很简单，就是利用这个用户名和密码连接一次ldap，连得上就成功，否则失败。

参考代码贴出来了，如下：

package com.test.ldap;

import java.util.Hashtable;

import javax.naming.AuthenticationException;
import javax.naming.Context;
import javax.naming.NamingEnumeration;
import javax.naming.NamingException;
import javax.naming.directory.DirContext;
import javax.naming.directory.SearchControls;
import javax.naming.directory.SearchResult;
import javax.naming.ldap.Control;
import javax.naming.ldap.InitialLdapContext;
import javax.naming.ldap.LdapContext;



public class UserAuthenticate {
    private String URL = "ldap://localhost:389/";
    private String BASEDN = "ou=catalogue,o=test.com";
    private String FACTORY = "com.sun.jndi.ldap.LdapCtxFactory";
    private LdapContext ctx = null;
    private Hashtable env = null;
    private Control[] connCtls = null;
   
   
    private void LDAP_connect(){
        env = new Hashtable();
        env.put(Context.INITIAL_CONTEXT_FACTORY,FACTORY);
        env.put(Context.PROVIDER_URL, URL+BASEDN);//LDAP server
        env.put(Context.SECURITY_AUTHENTICATION, "simple");
//此处若不指定用户名和密码,则自动转换为匿名登录
       
        try{
            ctx = new InitialLdapContext(env,connCtls);
        }catch(javax.naming.AuthenticationException e){
            System.out.println("Authentication faild: "+e.toString());
        }catch(Exception e){
            System.out.println("Something wrong while authenticating: "+e.toString());
        }
    }
   
   
    private String getUserDN(String email){
        String userDN = "";
       
        LDAP_connect();
       
        try{
               SearchControls constraints = new SearchControls();
               constraints.setSearchScope(SearchControls.SUBTREE_SCOPE);
               NamingEnumeration en = ctx.search("", "mail="+email, constraints); //The UID you are going to query,* means all nodes
               if(en == null){
                System.out.println("Have no NamingEnumeration.");
               }
               if(!en.hasMoreElements()){
                System.out.println("Have no element.");
               }
               while (en != null && en.hasMoreElements()){//maybe more than one element
                   Object obj = en.nextElement();
                   if(obj instanceof SearchResult){
                       SearchResult si = (SearchResult) obj;
                       userDN += si.getName();
                       userDN += "," + BASEDN;
                   }
                   else{
                       System.out.println(obj);
                   }
                   System.out.println();
               }
              }catch(Exception e){
               System.out.println("Exception in search():"+e);
              }
       
        return userDN;
    }
   
   
    public boolean authenricate(String ID,String password){
        boolean valide = false;
        String userDN = getUserDN(ID);
       
        try {
            ctx.addToEnvironment(Context.SECURITY_PRINCIPAL,userDN);
            ctx.addToEnvironment(Context.SECURITY_CREDENTIALS,password);
            ctx.reconnect(connCtls);
            System.out.println(userDN + " is authenticated");
            valide = true;
        }catch (AuthenticationException e) {
            System.out.println(userDN + " is not authenticated");
            System.out.println(e.toString());
            valide = false;
        }catch (NamingException e) {
            System.out.println(userDN + " is not authenticated");
            valide = false;
        }
       
        return valide;
    }
}

 

原来，一切这么简单。