一段应用在树型移动过程中的代码

最新推荐文章于 2024-08-14 02:10:41 发布

原创最新推荐文章于 2024-08-14 02:10:41 发布 · 167 阅读

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以前按照要求写过一个树型的分支移动的代码，具体的要求呢是当选中某一个节点时，这个节点的分支，通过修改树型结构中的节点的依次的顺序, 做上或者下的移动。主要是代码的结构，觉得有总结的必要


/**  
 * @pro_code  项目编码  
 * @selectId 选中的节点的ID  
 * @isUp 移动的方向    
 *  
 **/  
public void moveUpDown(String pro_code, Long selectId, Long isUp) {   
  try {   
       ProjectOrder selectOrder = dataOrderDao.getProjectOrder(pro_code, selectId);   
       List selectList = dataOrderDao.findBranch(selectOrder);   
       ProjectOrder targetOrder =    
         dataOrderDao.findTargetProjectOrder (selectOrder, isUp);   
       if (targetOrder == null)   
          throw new BusinessException("不能再移动");   
       List targetList = dataOrderDao.findBranch(targetOrder);   
       long selectLen = selectList.size();   
       long targetLen = targetList.size();   
       updateOrder(targetList, isUp == 2 ? -selectLen:selectLen);   
       updateOrder(selectList, isUp == 1 ? -targetLen:targetLen);   
       dataOrderDao.updateOrder(selectList);   
       dataOrderDao.updateOrder(targetList);   
} catch (Exception e) {   
    if (e instanceof BusinessException) throw (BusinessException) e;   
    LOG.error("移动出现错误", e);   
    throw new BusinessException("移动出现错误");   
}   
}

这只是当时写的，现在觉得有一点启发的代码，肯定有不足，希望给予指点。

经过修改和补充之后的代码：


/**
 * @projectCode  项目编码
 * @selectId 选中的节点的ID
 * @upDown 移动的方向 0:down 1:up
 **/
public void moveBranch(String projectCode, Long selectId, Integer upDown) {
  try {
       ProjectOrder startOrder = dataOrderDao.getProjectOrder(projectCode, selectId);
       List nowBranch = getBranch(startOrder); 
       ProjectOrder targetOrder = findTargetOrder(startOrder, upDown);
       List targetBranch = getBranch(targetOrder); 
       updateNowBranch(nowBranch, upDown, targetBranch.size());
       updateTargetBranch(targetBranch,upDown, nowBranch.size());
  } catch (Exception e) {
    if (e instanceof BusinessException) throw (BusinessException) e;
    LOG.error("移动出现错误", e);
    throw new BusinessException("移动出现错误");
  }
}
private void updateNowBranch(List nowBranch, Integer upDown, Long size) {
     updateBranchOrder(nowBranch, upDown == 1 ? -size : size);
}
private void updateTargetBranch(List targetBranch, Integer upDown, Long size) {
     updateBranchOrder(targetBranch, upDown == 1 ? size : -size);
}
private ProjectOrder findTargetOrder(ProjectOrder startOrder, Integer upDown) {
     ProjectOrder targetOrder = 
        dataOrderDao.findTargetProjectOrder (startOrder, upDown);
     return targetOrder;
}
private List getBranch(ProjectOrder startOrder) {
       if (startOrder == null)
	      throw new BusinessException("不能再移动");
       List branch = dataOrderDao.findBranch(startOrder);
       return branch
}
private void updateBranchOrder(List branch, long size){
        updateOrder(branch, size);
        dataOrderDao.updateOrder(branch);
}
private void updateOrder(List<ProjectOrder> branch, long size) {
   for (ProjectOrder each : branch) {
       order.setOrder_num(each.getOrder_num() + size);
   }
}