python26实例[文件copy和自动rename]

最新推荐文章于 2021-03-01 11:15:35 发布

原创最新推荐文章于 2021-03-01 11:15:35 发布 · 452 阅读

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本文介绍了一款Python脚本工具，该工具可以智能地复制文件或文件夹，并在目标位置已有同名文件或文件夹时自动进行重命名，避免覆盖原有文件。此工具适用于需要频繁复制文件并保留所有版本的场景。

用来copy文件和目录，当文件或文件夹已经存在时，自动增加.r1,.r2......来重命名新copy的文件。

代码：

import os
import sys
import shutil

def copyWithRename(source, dest, rename = True):

  if os.path.exists(dest) and rename == True:
    dir, name = os.path.split(dest)
    newdest = dest
    if os.path.isfile(dest):
      namewithoutext, ext = os.path.splitext(name)
      i = 1
      while(1):
        newdest = os.path.join(dir, namewithoutext + '.r' + str(i) + ext)
        if os.path.exists(newdest):
          i+=1
          continue
        else: break
    else:
      i = 1
      while(1):
        newdest = os.path.join(dir, name + '.r' + str(i))
        if os.path.exists(newdest):
          i+=1
          continue
        else: break
    dest = newdest

  print 'Copied : ' + source + '  >>>  ' + dest

  if os.path.isdir(source):
    shutil.copytree(source,dest)
  else:
    shutil.copyfile(source,dest)


def usage():
  thescript = sys.argv[0]
  usage = '\n\
  Function:\n\
    Copy file or folder and rename it with .rx suffix\n\
    when the same file or folder is already existed.\n\
  Usage:\n\
    python %s source dest\n\
  Eexamples:\n\
    python %s "c:\\test\\test.txt" "c:\\test2\\test.txt"\n\
    python %s "c:\\test\\test1" "c:\\test\\test2"\n\
  Notes:\n\
      source and dest must be same type, such as both of them are file or dir.\n\
  ' % (thescript,thescript,thescript)
  print usage

if __name__ == '__main__':
  if len(sys.argv) == 3:
    copyWithRename(sys.argv[1], sys.argv[2])
  else:
    usage()

完！