讲每个任务以及每个星期的每一天作为节点。。
连S 到 每个人物为 要求天数的流量
如果那天能做那个任务,就任务与天连边,容量1
每天都连到T点,容量1
最后判断是否流量是否是总工作天数
//tpl
//ipqhjjybj_tpl.h
//header.h
#include <cstdio>
#include <cstdlib>
#include <map>
#include <set>
#include <algorithm>
#include <cstring>
#include <iostream>
#include <vector>
#include <string>
#define mp(x,y) make_pair(x,y)
#define pii pair<int,int>
#define pLL pair<long long ,long long>
#define rep(i,j,k) for(int i = j; i < k;i++)
#define repn(i,j,k) for(int i = j; i <= k;i++)
using namespace std;
const int INF = 0x3f3f3f3f;
const int N = 1111;
int tot;
int s,t;
int sum;
struct node{
int u,v,w,next;
node(){}
node(int _u,int _v,int _w,int _next){
u=_u,v=_v,w=_w,next=_next;
}
}edge[N*N];
int head[N],cur[N],dis[N];
int pre[N],gap[N],aug[N];
const int oo=0x3f3f3f;
void addEdge(int u,int v,int w){
edge[tot]=node(u,v,w,head[u]);
head[u]=tot++;
edge[tot]=node(v,u,0,head[v]);
head[v]=tot++;
}
int SAP(int s,int e,int n){
int max_flow=0,v,u=s;
int id,mindis;
aug[s]=oo;
pre[s]=-1;
memset(dis,0,sizeof(dis));
memset(gap,0,sizeof(gap));
gap[0]=n;
for(int i=0;i <= n;i++)
cur[i]=head[i];
while(dis[s]<n){
if(u==e){
max_flow += aug[e];
for(v=pre[e]; v!=-1; v=pre[v]){
int ed=cur[v];
edge[ed].w -= aug[e];
edge[ed^1].w += aug[e];
aug[v]-=aug[e];
if(edge[ed].w==0) u=v;
}
}
bool flag=false;
for(id=cur[u]; id!=-1;id=edge[id].next){
v=edge[id].v;
if(edge[id].w > 0 && dis[u]==dis[v]+1){
flag=true;
pre[v]=u;
cur[u]=id;
aug[v]=min(aug[u],edge[id].w);
u=v;
break;
}
}
if(flag==false){
if(--gap[dis[u]] == 0) break;
int mindis=n;
for(id=head[u]; id!=-1; id=edge[id].next){
v=edge[id].v;
if(edge[id].w>0 && dis[v] < mindis){
mindis = dis[v];
cur[u]=id;
}
}
dis[u] = mindis + 1;
gap[dis[u]]++;
if(u!=s)u=pre[u];
}
}
return max_flow;
}
int n,m;
int kk[10];
int main(){
int tt;
scanf("%d",&tt);
while(tt--){
scanf("%d",&n);
tot=sum=s=0;
t=1;
memset(head,-1,sizeof(head));
int maxFlow = 0;
int tmp;
int maxWeek = 0;
rep(i,0,n){
rep(j,1,10){
scanf("%d",kk+j);
}
maxFlow += kk[8];
maxWeek = max(maxWeek,kk[9]);
addEdge(s,i+2,kk[8]);
rep(j,1,8){
if(kk[j])
rep(z,0,kk[9]){
addEdge(i+2,n+1+z*7+j,1);
}
}
}
rep(j,1,8){
rep(z,0,maxWeek){
addEdge(n+1+z*7+j,t,1);
}
}
int ans = SAP(s,t,n+1+(maxWeek-1)*7+8);
//printf("ans=%d maxFlow=%d\n",ans,maxFlow);
if(ans >= maxFlow)puts("Yes");
else puts("No");
}
return 0;
}