imut zcy,I promise You.

/*高精度的Catalan数题目 公式： h ( n ) = h ( n - 1 ) * ( 4 * n - 2 ) / n + 1 */ Source Code Problem: 2084   User: imutzcy Memory: 296K   Time: 0MS Language: C++   Result: Accepted

/*高精度的Catalan数题目   公式：   h ( n ) = h ( n - 1 ) * ( 4 * n - 2 ) / n + 1   */ Problem : 1023 ( Train Problem II )     Judge Status : Accepted RunId : 7618448    Language : G++    Author : CherryChou

跟着Bin哥一起学。 #include #include #include #include #include using namespace std; const double PI=acos(-1.0); struct Complex { double x,y; Complex(double _x=0.0,double _y=0.0) { x=_x; y=_y;

#include #include #include #include #include #define eps 1e-8 using namespace std; int main() { int a,b,c,d; while(~scanf("%d%d%d%d",&a,&b,&c,&d)) { double num1=b*log(a); double num2=d*l