小试geany

最新推荐文章于 2025-03-06 13:14:57 发布

ifishland

最新推荐文章于 2025-03-06 13:14:57 发布

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分类专栏： c

本文链接：https://blog.youkuaiyun.com/ifishland/article/details/24675059

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本文介绍了一个C语言程序，该程序可以实现从一个字符串中移除所有出现在另一个字符串中的字符。通过对字符串进行遍历和查找，利用基本的字符串操作函数完成了这一任务。

摘要生成于 C知道，由 DeepSeek-R1 满血版支持，前往体验 >

geany这个工具在windows下使用居然有点略卡，编译过程，avast报警。。总体来说还比较好用，gnu c比ansi c好用不少。

小程序取自C程序设计语言里的题目2.4，实现了将字符串1中与字符串2中的相同字符剔除。

/*
 * squeeze.c
 * 
 * Copyright 2014 Administrator <fishland>
 * 
 * This program is free software; you can redistribute it and/or modify
 * it under the terms of the GNU General Public License as published by
 * the Free Software Foundation; either version 2 of the License, or
 * (at your option) any later version.
 * 
 * This program is distributed in the hope that it will be useful,
 * but WITHOUT ANY WARRANTY; without even the implied warranty of
 * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
 * GNU General Public License for more details.
 * 
 * You should have received a copy of the GNU General Public License
 * along with this program; if not, write to the Free Software
 * Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston,
 * MA 02110-1301, USA.
 * 
 * 
 */


#include <stdio.h>
#include <string.h>
#include <malloc.h>

int find(char*str, char c)
{
	int strlength = strlen(str);
	int i;
	int ret = -1;
	for(i = 0; i != strlength; i++)
	{
		if(str[i] == c)
		{
			ret = i;
		}	
	}
	return ret;
}

int del_char(char* str, int ofs)
{
	int i, ret = 0;
	int strlength = strlen(str);
	
	if(ofs > strlength)
	{
		printf("invalid value..!\n");
		ret = -1;
	}
	for(i = ofs; i < strlength; i++)
	{
		str[i] = str[i + 1];
	}
	return ret;
}

void squeeze(char* str1, char* str2)
{
	if(str1 == NULL || str2 == NULL)
	{
		printf("error..!\n");
	}
	
	int strlength = strlen(str2);
	char* col = (char*)malloc(strlength);
	int i, j;
	for(i = 0; i != strlength; i++)
	{
		while((j = find(str1, str2[i])) != -1)
			del_char(str1, j); 
	}
	free(col);
}

int main(int argc, char **argv)
{
	char str1[] = "aaabbbcccdddfdasfjlajflajlajlfasflasflasjlas";
	char str2[] = "afs";
	printf("str1 = %s\n", str1);
	printf("str2 = %s\n", str2);
	printf("squeezing..!\n");
	squeeze(str1, str2);
	printf("str1 is squeezed to %s\n", str1);
	return 0;
}