用字符串替换空格

用字符串%20替换空格

void Instead(char *string,int length)
{
	assert(string);
	int count = 0;
	int size = 0;
	int i = 0;
	while(string[i] != '\0')
	{
		if(string[i] == ' ')
		{
			count++;
		}
		i++;
		size++;
	}
	int newlength = size+count*2;
	if(length < newlength)
	{
		return;
	}
	//从后向前依次替换
	while(newlength>=0 && size>=0)
	{
		if(string[size] == ' ')
		{
	        string[newlength--] = '0';
			string[newlength--] = '2';
			string[newlength--] = '%';
		}
		else
		{
			string[newlength--] = string[size];
		}
		size--;
	}
}

相关题(从尾到头比较大小，将元素放在合适的位置)
两个有序数组A1和A2,将A2中的所有数字复制到A1中，要求复制后的A1有序

int main()
{
	int arr1[12] = {1,2,5,7,9};
	int arr2[] = {4,6,8,10};
	int len1 = 4;
	int len2 =sizeof(arr2)/sizeof(arr2[0])-1;
	while(len1>=0 && len2>=0)
	{
		if(arr2[len2]>arr1[len1])
		{
		   arr1[len1+len2+1] = arr2[len2];
		   len2--;
		}
		else
		{
			arr1[len1+len2+1] = arr1[len1];
			len1--;
		}
	}
	if(arr1[0] > arr2[0])
	{
		arr1[0] = arr2[0];
	}

	system("pause");
	return 0;
}