Sum Problem
Time Limit: 1000/500 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 448087 Accepted Submission(s): 112622
Problem Description
Hey, welcome to HDOJ(Hangzhou Dianzi University Online Judge).
In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.
In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.
Input
The input will consist of a series of integers n, one integer per line.
Output
For each case, output SUM(n) in one line, followed by a blank line. You may assume the result will be in the range of 32-bit signed integer.
Sample Input
1 100
Sample Output
1 5050code:import java.util.*; public class Main{ public static void main(String[] args){ Scanner in=new Scanner(System.in); while(in.hasNextInt()){ int n=in.nextInt(); int sum=0; for(int i=1;i<=n;i++) sum+=i; System.out.println(sum+"\n\n"); } } }

379

被折叠的 条评论
为什么被折叠?



