力扣，12整数转罗马java代码

最新推荐文章于 2025-09-05 16:34:31 发布

原创最新推荐文章于 2025-09-05 16:34:31 发布 · 180 阅读

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本文介绍了一种将整数转换为罗马数字的算法实现。通过定义数字与罗马符号之间的映射关系，并采用循环和条件判断的方式进行转换，最终得到对应的罗马数字字符串。

class Solution {
    public String intToRoman(int num) {
        int numCopy = num;
		String value = "";
		int index = 6;
		int[] nums = new int[7];
		String[] str = new String[7];
		nums[0] = 1;
		str[0] = "I";
		nums[1] = 5;
		str[1] = "V";
		nums[2] = 10;
		str[2] = "X";
		nums[3] = 50;
		str[3] = "L";
		nums[4] = 100;
		str[4] = "C";
		nums[5] = 500;
		str[5] = "D";
		nums[6] = 1000;
		str[6] = "M";
		
		while(numCopy>0) {
			
			for(int i=index;i>=0;i--){
				
				if(i%2==0) {
					if(numCopy>=nums[i]) {
						numCopy = numCopy-nums[i];
						value+=str[i];
						index = i;
						break;
					}else if(i>0) {
						if(numCopy>=(nums[i-1]+4*nums[i-2])) {
							numCopy = numCopy-(nums[i-1]+4*nums[i-2]);
							value+=str[i-2];
							value+=str[i];
						}
					}
					
				}else {
					if(numCopy>=nums[i]) {
						numCopy = numCopy-nums[i];
						value+=str[i];
						index = i;
						break;
					}else {
						if(numCopy>=(4*nums[i-1])) {
							numCopy = numCopy-4*nums[i-1];
							value+=str[i-1];
							value+=str[i];
							index = i;
							break;
						}
						
					}
					
				}
					
			}
			
		}
        return value;
    }
}