题目:
A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null.
Return a deep copy of the list.
The Linked List is represented in the input/output as a list of n nodes. Each node is represented as a pair of [val, random_index] where:
val: an integer representingNode.valrandom_index: the index of the node (range from0ton-1) where random pointer points to, ornullif it does not point to any node.
Example 1:

Input: head = [[7,null],[13,0],[11,4],[10,2],[1,0]] Output: [[7,null],[13,0],[11,4],[10,2],[1,0]]
Example 2:

Input: head = [[1,1],[2,1]] Output: [[1,1],[2,1]]
Example 3:

Input: head = [[3,null],[3,0],[3,null]] Output: [[3,null],[3,0],[3,null]]
Example 4:
Input: head = [] Output: [] Explanation: Given linked list is empty (null pointer), so return null.
Constraints:
-10000 <= Node.val <= 10000Node.randomis null or pointing to a node in the linked list.- Number of Nodes will not exceed 1000.
代码:
/**
* Definition for singly-linked list with a random pointer.
* struct RandomListNode {
* int label;
* RandomListNode *next, *random;
* RandomListNode(int x) : label(x), next(NULL), random(NULL) {}
* };
*/
class Solution {
public:
RandomListNode *copyRandomList(RandomListNode *head) {
if(head == NULL)
return head;
RandomListNode* c_head = new RandomListNode(head->label);
for(RandomListNode* p = head->next, *q = c_head; p != NULL; p = p->next)
{
q->next = new RandomListNode(p->label);
q = q->next;
}
for(RandomListNode* p = head, *q = c_head; p != NULL; p = p->next, q = q->next)
{
for(RandomListNode* r = head, *s = c_head; r != NULL; r = r->next, s = s->next)
{
if(p->random == r)
{
q->random = s;
break;
}
}
}
return c_head;
}
};
深拷贝含随机指针链表
本文介绍了一种复杂链表结构的深拷贝方法,该链表每个节点包含一个额外的随机指针,指向链表中的任意节点或空。通过创建新链表并逐一复制节点和随机指针,实现链表的完全复制。
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