题目:
Given an array with n objects colored red, white or blue, sort them in-place so that objects of the same color are adjacent, with the colors in the order red, white and blue.
Here, we will use the integers 0, 1, and 2 to represent the color red, white, and blue respectively.
Note: You are not suppose to use the library's sort function for this problem.
Example:
Input: [2,0,2,1,1,0] Output: [0,0,1,1,2,2]
Follow up:
- A rather straight forward solution is a two-pass algorithm using counting sort.
First, iterate the array counting number of 0's, 1's, and 2's, then overwrite array with total number of 0's, then 1's and followed by 2's. - Could you come up with a one-pass algorithm using only constant space?
代码:
class Solution {
public:
void sortColors(vector<int>& nums) {
vector<int> record(3, 0);
for(int i = 0; i<nums.size(); i++)
record[nums[i]]++;
int idx = 0;
for(int i = 0; i<3; i++)
{
for(int j = 0; j<record[i]; j++)
nums[idx++] = i;
}
return;
}
};
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