项目1-Complex类(第九周)-优快云博客

本文介绍了一个使用C++实现的复数类，通过运算符重载实现了复数的加、减、乘、除操作。文章提供了完整的源代码示例，并展示了如何通过重载输入输出流来简化复数的输入和输出。

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上机目的：运算符重载

/*
* 程序的版权和版本声明部分
* Copyright (c)2012, 烟台大学计算机学院学生
* All rightsreserved.
* 文件名称： fun.cpp
* 作 者：黄兆宽
* 完成日期：2013 年 4 月 26 日
* 版本号： v1.0
* 对任务及求解方法的描述部分：函数运算符重载问题。
* 输入描述：略
* 问题描述：略
* 程序输出：如下
*/
#include <iostream>
using namespace std;
class Complex
{
public:
	Complex(){real=0;imag=0;}
	Complex(double r,double i){real=r;imag=i;}

	friend istream&operator>>(istream&,Complex&);
	friend ostream&operator<<(ostream&,Complex&);
	Complex operator+(Complex &c2);
	Complex operator-(Complex &c2);
	Complex operator*(Complex &c2);
	Complex operator/(Complex &c2);
	void display();
private:
	double real;
	double imag;
};

//复数相加： (a+bi)+(c+di)=(a+c)+(b+d)i. 
ostream&operator<<(ostream& output,Complex& c)
{
	output<<"("<<c.real<<","<<c.imag<<"i)";
	return output;
}
istream&operator>>(istream& input,Complex& c)
{
	cout<<"请输入虚数的实部与虚部：";
	input>>c.real>>c.imag;
	return input;
}
Complex Complex::operator+(Complex &c2)
{
	Complex c;
	c.real=real+c2.real;
	c.imag=imag+c2.imag;
	return c;
}
//复数相减：(a+bi)-(c+di)=(a-c)+(b-d)i.
Complex Complex::operator-(Complex &c2)
{
	Complex c;
	c.real=real-c2.real;
	c.imag=imag-c2.imag;
	return c;
}
//复数相乘：(a+bi)(c+di)=(ac－bd)+(bc+ad)i.
Complex Complex::operator*(Complex &c2)
{
	Complex c;
	c.real=real*c2.real-imag*c2.imag;
	c.imag=imag*c2.real+real*c2.imag;
	return c;
}

//复数相除：(a+bi)/(c+di)=(ac+bd)/(c^2+d^2) +(bc-ad)/(c^2+d^2)i 
Complex Complex::operator/(Complex &c2)
{
	Complex c;
	c.real=(real*c2.real+imag*c2.imag)/(c2.real*c2.real+c2.imag*c2.imag);
	c.imag=(imag*c2.real-real*c2.imag)/(c2.real*c2.real+c2.imag*c2.imag);
	return c;
}

void Complex::display()
{
	cout<<"("<<real<<","<<imag<<"i)"<<endl;
}

int main()
{
	Complex c1,c2,c3;
	cin>>c1>>c2;
	cout<<"c1="<<c1<<endl;
	cout<<"c2="<<c2<<endl;
	c3=c1+c2;
	cout<<"c1+c2="<<c3<<endl;
	c3=c1-c2;
	cout<<"c1-c2="<<c3<<endl;
	c3=c1*c2;
	cout<<"c1*c2="<<c3<<endl;
	c3=c1/c2;
	cout<<"c1/c2="<<c3<<endl;
	return 0;
}