HDU6045+Is Derek lying?(思路)+多校联赛第二场

本文介绍了一道算法题目,需要判断德瑞克在一场选择题考试中是否对其朋友阿尔菲亚说了谎。通过对比两人的答案并结合给出的分数,来确定德瑞克的回答是否真实。

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Is Derek lying?

Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 1000    Accepted Submission(s): 545


Problem Description
Derek  and  Alfia  are good friends. Derek  is Chinese,and  Alfia  is Austrian.This summer holiday,they both participate in the summer camp of Borussia Dortmund.During the summer camp,there will be fan tests at intervals.The test consists of  N  choice questions and each question is followed by three choices marked “ A ” “ B ” and “ C ”.Each question has only one correct answer and each question is worth  1  point.It means that if your answer for this question is right,you can get  1 point.The total score of a person is the sum of marks for all questions.When the test is over,the computer will tell  Derek  the total score of him and  Alfia .Then  Alfia  will ask  Derek  the total score of her and he will tell her: “My total score is  X ,your total score is  Y .”But  Derek  is naughty,sometimes he may lie to her. Here give you the answer that  Derek  and  Alfia  made,you should judge whether  Derek  is lying.If there exists a set of standard answer satisfy the total score that  Derek said,you can consider he is not lying,otherwise he is lying.
 

Input
The first line consists of an integer  T ,represents the number of test cases.

For each test case,there will be three lines.

The first line consists of three integers  N , X , Y ,the meaning is mentioned above.

The second line consists of  N  characters,each character is “ A ” “ B ” or “ C ”,which represents the answer of  Derek  for each question.

The third line consists of  N  characters,the same form as the second line,which represents the answer of  Alfia  for each question.

Data Range: 1N80000 , 0X,YN, Ti=1N300000
 

Output
For each test case,the output will be only a line.

Please print “ Lying ” if you can make sure that  Derek  is lying,otherwise please print “ Not lying ”.
 

Sample Input
  
2 3 1 3 AAA ABC 5 5 0 ABCBC ACBCB
 

Sample Output
  
Not lying Lying
 

Source
 

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#include<stdio.h>
#include<iostream>
#include<algorithm>
#include<string.h>
#include<math.h>
using namespace std;
char a[100010];
char b[100010];
int main()
{
    int t,n,m,x,y,sum;
    scanf("%d",&t);
    while(t--)
    {
        scanf("%d%d%d",&n,&x,&y);
        sum=0;
        scanf("%s",a);
        scanf("%s",b);
        for(int i=0; i<n; i++)
        {
            if(a[i]==b[i])
                sum++;
        }
        if(x<y)
        {
            m=x;
            x=y;
            y=m;
        }
         if((x+y-sum<=n)&&(x-y+sum<=n))
            printf("Not lying\n");
        else
            printf("Lying\n");
    }
}



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