Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.
You may assume no duplicates in the array.
Here are few examples.
[1,3,5,6], 5 → 2
[1,3,5,6], 2 → 1
[1,3,5,6], 7 → 4
[1,3,5,6], 0 → 0
Show Similar Problems
class Solution(object):
def searchInsert(self, nums, target):
"""
:type nums: List[int]
:type target: int
:rtype: int
"""
low = 0
high = len(nums) - 1
while low <= high:
mid = low + (high - low) / 2
if nums[mid] < target:
low = mid + 1
elif nums[mid] > target:
high = mid - 1
else:
return mid
return low

本文详细解释了如何在一个已排序的整数数组中查找目标值的正确插入位置,确保数组保持有序。通过使用二分查找算法,提高了搜索效率。文章提供了代码示例并解释了每一步的操作原理。
167

被折叠的 条评论
为什么被折叠?



