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%Input - f is the integrand input as a string ¡¯f¡¯
% - a and b are upper and lower limits of integration
% - tol is the tolerance
% Output - SRmat is the table of values
% - quad is the quadrature value
% - err is the error estimate
%Initialize values
SRmat = zeros(30, 6);
iterating=0;
done=1;
SRvec=zeros(1, 6);
SRvec=srule(f, a, b, tol);
SRmat(1, 1:6)=SRvec;
m=1;
state=iterating;
while(state==iterating)
n=m;
for j=n:-1:1
p=j;
SR0vec=SRmat(p,:);
err=SR0vec(5);
tol=SR0vec(6);
if (tol<=err)
%Bisect interval,apply Simpson¡¯s rule
%recursively, and determine error
state=done;
SR1vec=SR0vec; SR2vec=SR0vec;
a=SR0vec(1); b=SR0vec(2); c=(a+b)/2;
err=SR0vec(5); tol=SR0vec(6); tol2=tol/2;
SR1vec=srule(f,a,c,tol2);
SR2vec=srule(f,c,b,tol2);
err=abs(SR0vec(3)-SR1vec(3)-SR2vec(3))/10;
%Accuracy test
if (err<tol)
SRmat(p, :)=SR0vec;
SRmat(p,4)=SR1vec(3)+SR2vec(3); SRmat(p,5)=err;
else
SRmat(p+1:m+1,:)=SRmat(p:m,:);
m=m+1;
SRmat(p,:)=SR1vec; SRmat(p+1,:)=SR2vec;
state=iterating;
end
end
end
end
quad=sum(SRmat(:,4));
err=sum(abs(SRmat(:,5)));
SRmat=SRmat(1:m,1:6);
srule.m
%Program7.5(Simpson's Rule)
function Z=srule(f,a,b,tol)
%Input- f is the integrand input as a string ??f??
%- a and b are upper and lower limits of integration
%- tol is the tolerance
% Output - Z is a 1x6 vector [a b < xmlnamespace prefix ="st1" ns ="urn:schemas-microsoft-com:office:smarttags" />S S2 err tol1]
h=(b-a)/2;
C=zeros(1,3);
C=feval(f,[a (a+b)/2 b]);
S=h*(C(1)+4*C(2)+C(3))/3;
S2=S;
tol1=tol;
err=tol;
Z=[a b S S2 err tol1];
fun.m
function f=fun(x)
f=sin(4*x).*exp(-2*x);
Untitled.m
a=0;
b=3;
tol=0.00001;
f='fun';
[SRmat, quad, err]=adapt(f, a, b, tol)
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驽马点滴 和视频空间
哔哩哔哩-《挨踢日志》