设计思路:
- 依据题目要求输出即可
编译器:C (gcc)
#include <stdio.h>
int main()
{
int m, n, a, b, k;
int i, j, tmp;
scanf("%d %d %d %d %d", &m, &n, &a, &b, &k);
for (i = 0; i < m; i++) {
for (j = 0; j < n; j++) {
scanf("%d", &tmp);
if (a <= tmp && tmp <= b)
tmp = k;
printf("%03d%c", tmp, j == n - 1 ? '\n' : ' ');
}
}
return 0;
}