HDU2057 A + B Again

最新推荐文章于 2024-07-21 10:00:00 发布

huadong_fcy56

最新推荐文章于 2024-07-21 10:00:00 发布

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分类专栏：输入技巧 HDU 简单模拟

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本文介绍了一个简单的十六进制加法问题及其解决方案。该问题要求输入两个十六进制整数并输出它们的和。文章提供了一段C++代码示例，用于演示如何实现这一功能。

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Problem Description

There must be many A + B problems in our HDOJ , now a new one is coming.
Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too.
Easy ? AC it !

Input

The input contains several test cases, please process to the end of the file.
Each case consists of two hexadecimal integers A and B in a line seperated by a blank.
The length of A and B is less than 15.

Output

For each test case,print the sum of A and B in hexadecimal in one line.

Sample Input

  
   +A -A
+1A 12
1A -9
-1A -12
1A -AA

Sample Output

Author

linle

Source

校庆杯Warm Up

HDU2057
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<cstdlib>
using namespace std;
int main()
{
	 long long  a,b;
	 while(~scanf("%llX%llX",&a,&b)){
			if(a+b<0) {
				a=-a;b=-b;
				cout<<"-";
			}
			printf("%llX\n",a+b);
	 }
	 return 0;
}

("%X",a)表示16进制处理a，x时是小写