Task function must be specified

在执行gulp命令时控制台报错:

Task function must be specified

解决方法:

1.使用gulp -v 查看gulp的Local version版本和package.json里面的版本是否相同

如果相同,切是4.0的版本编写的的方法查看是否为如下代码,

4.0错误的写法:

gulp.task('default', ['del'], function() {
    // default task code here
});

修改为最新的正确写法:

gulp.task('default', gulp.series('del', function() { 
    // default task code here
}));

 

Thank you for your question. Based on your statement, I understand that you want me to improve an application developed in Task 1 to ensure that users can only input valid values, i.e., a 4/5 number between 1 and 10 (inclusive). To achieve this, I can add input validation to the existing code. Here's how I would do it: 1. First, I would remove the 'Check!' button as you suggested since it is no longer necessary. 2. Next, I would modify the existing code to prompt the user to enter a valid input if they enter an invalid value. For example, if the user enters a value that is not a number or is not between 1 and 10, the program will display an error message and ask the user to enter a valid input. 3. Finally, I would implement a loop that will continue to prompt the user to enter a valid input until they do so. Once the user enters a valid input, the program will proceed with the calculations as specified in Task 1. Here's a sample code snippet that demonstrates how I would implement the input validation: ``` while True: try: x = int(input("Please enter a 4/5 number between 1 and 10 (inclusive): ")) if x >= 1 and x <= 10 and (x == 4 or x == 5): break else: print("Invalid input! Please enter a valid 4/5 number between 1 and 10 (inclusive).") except ValueError: print("Invalid input! Please enter a valid 4/5 number between 1 and 10 (inclusive).") # Perform calculations using valid input value x ``` This code will keep prompting the user to enter a valid input until they do so. Once a valid input is entered, the code will proceed with the calculations as specified in Task 1. I hope this helps!
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