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CodeForces 618B (找规律)
CodeForces 618BDescriptionBob has a permutation of integers from 1 to n. Denote this permutation as p. Thei-th element of p will be denoted aspi. For all pairs of distinct integers原创 2016-03-30 22:11:21 · 563 阅读 · 0 评论 -
Infinite Sequence
Infinite SequenceCrawling in process...Crawling failedTime Limit:1000MS Memory Limit:262144KB 64bit IO Format:%I64d & %I64u SubmitStatus Practice CodeForces 622A Des原创 2016-03-12 19:36:54 · 584 阅读 · 0 评论 -
Tricky Sum(等比数列)
Tricky SumCrawling in process...Crawling failedTime Limit:1000MS Memory Limit:262144KB 64bit IO Format:%I64d & %I64u SubmitStatus Practice CodeForces 598A Descriptio原创 2016-03-12 18:36:50 · 653 阅读 · 0 评论 -
Divisibility（区间）
DivisibilityCrawling in process...Crawling failedTime Limit:1000MS Memory Limit:262144KB 64bit IO Format:%I64d & %I64u SubmitStatus Practice CodeForces 597A Descript原创 2016-03-12 19:43:25 · 346 阅读 · 0 评论 -
Interview（位运算）
InterviewCrawling in process...Crawling failedTime Limit:1000MS Memory Limit:262144KB 64bit IO Format:%I64d & %I64u SubmitStatus Practice CodeForces 631A Description原创 2016-03-12 20:11:49 · 460 阅读 · 0 评论 -
Game
GameCrawling in process...Crawling failedTime Limit:500MS Memory Limit:65536KB 64bit IO Format:%I64d & %I64uSubmitStatus DescriptionThere is a legend in the IT City原创 2016-03-12 21:31:02 · 336 阅读 · 0 评论 -
CodeForces 628C
CodeForces 628C DescriptionLimak is a little polar bear. He likes nice strings — strings of lengthn, consisting of lowercase English letters only.The distance between two letters is def原创 2016-04-22 22:10:57 · 771 阅读 · 0 评论