#include <iostream>
#include <cstring>
#include <algorithm>
using namespace std;
const int N = 10;
int n;
int col[N], dg[N + N], rdg[N + N]; // 列占用
// 正对角线占用
// 副对角线占用
char table[N][N]; // 棋盘
void dfs(int index)
{
if(index == n) // 结束条件
{
for (int i = 0; i < n; i ++ )
{
for (int j = 0; j < n; j ++ )
cout << table[i][j];
cout << endl;
}
cout << endl;
return;
}
for (int j = 0; j < n; j ++ )
{
// n - index = b + j + 1 正对角线 (b会为负,要再加上n)
// n - index = b - (j + 1) 副对角线
if(!col[j] && !dg[n - index - j - 1 + n] && !rdg[n - index + j + 1])
{
col[j] = dg[n - index - j - 1 + n] = rdg[n - index + j + 1] = 1;
table[index][j] = 'Q';
dfs(index + 1);
table[index][j] = '.'; // 搜索完恢复
col[j] = dg[n - index - j - 1 + n] = rdg[n - index + j + 1] = 0;
}
}
}
int main()
{
cin >> n;
for (int i = 0; i < n; i ++ )
for (int j = 0; j < n; j ++ )
table[i][j] = '.';
dfs(0);
return 0;
}
AcWing 843. n-皇后问题
于 2024-01-14 13:08:52 首次发布