Servlet学习02

最新推荐文章于 2023-04-10 07:55:29 发布

原创最新推荐文章于 2023-04-10 07:55:29 发布 · 92 阅读

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文章标签：

#servlet #maven #tomcat #java

Servlet学习

1.请求转发

protected void doGet(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {
        ServletContext context = this.getServletContext();
        context.getRequestDispatcher("/gp").forward(req,resp);
    }

1.请求转发时，页面不变，地址变化

2.读取资源文件

protected void doGet(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {
        ServletContext context = this.getServletContext();
        InputStream is = context.getResourceAsStream("/WEB-INF/classes/db.properties");
        Properties prop = new Properties();
        prop.load(is);
        String name = prop.getProperty("username");
        String pwd = prop.getProperty("password");
        resp.getWriter().print(name+":"+pwd);
    }

1.在resources目录下创建db.properties
2.如果需要在java目录下创建properties可以在pom.xml中加上

 <resource>
                <directory>src/main/java</directory>
                <includes>
                    <include>**/*.properties</include>
                    <include>**/*.xml</include>
                </includes>
                <filtering>true</filtering>
            </resource>