
矩阵快速幂
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AnICoo1
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HDOJ 1575 Tr A (矩阵快速幂)
Tr ATime Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3837 Accepted Submission(s): 2868Problem DescriptionA为一个方阵,则Tr A表示A的迹(就是主对角线上原创 2016-01-13 14:54:59 · 407 阅读 · 0 评论 -
HDOJ 1757 A Simple Math Problem (矩阵快速幂)
A Simple Math ProblemTime Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3695 Accepted Submission(s): 2214Problem DescriptionLele now原创 2016-01-13 14:39:05 · 378 阅读 · 0 评论 -
HDOJ 4920 Matrix multiplication (矩阵相乘)
Matrix multiplicationTime Limit: 4000/2000 MS (Java/Others) Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 3838 Accepted Submission(s): 1576Problem DescriptionGiven原创 2015-11-07 13:03:48 · 400 阅读 · 0 评论 -
POJ 3070 Fibonacci (矩阵快速幂求fibonacci)
FibonacciTime Limit: 1000MS Memory Limit: 65536KTotal Submissions: 11439 Accepted: 8134DescriptionIn the Fibonacci integer sequence, F0 = 0, F1 = 1, andFn = Fn原创 2015-11-06 21:45:07 · 420 阅读 · 0 评论 -
NYOJ 623 A*B(2)(矩阵相乘)
描述 ACM的C++同学有好多作业要做,最头痛莫过于线性代数了,因为每次做到矩阵相乘的时候,大量的乘法都会把他搞乱,所以他想请你写个程序帮他检验一下计算结果是否正确。输入有多组测试数据,每行给出一组m,n,k(0矩阵A:m行n列。矩阵B:n行k列。接下来给出m*n个数表示矩阵A和n*k个数表示矩阵B,对于每个数s,0当m,n,k同时为0时结束。输出计算两个矩阵的乘积并输出。样例原创 2015-06-12 14:16:43 · 502 阅读 · 0 评论