题意
判断一棵树是否是二叉排序树
思路
递归中维护当前子树的最大值和最小值,左子树维护最大值,右子树维护最小值,然后进行判断
代码
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
bool isValidBST(TreeNode* root) {
return isValid(root, NULL, NULL);
}
bool isValid(TreeNode* node, TreeNode* minNode, TreeNode* maxNode){
if(node == NULL){
return true;
}
if((minNode && node->val <= minNode->val) || (maxNode && node->val >= maxNode->val)){
return false;
}
return isValid(node->left, minNode, node) && isValid(node->right, node, maxNode);
}
};