1、学生选课信息查询
teacher 教师表
student 学生表
cource 课程表
studentcource 选课表 学生和课程的关系表
准备工作:
CREATE TABLE teacher (
id int(11) NOT NULL primary key auto_increment,
name varchar(20) not null unique
);
CREATE TABLE student (
id int(11) NOT NULL primary key auto_increment,
name varchar(20) NOT NULL unique,
city varchar(40) NOT NULL,
age int
) ;
CREATE TABLE course(
id int(11) NOT NULL primary key auto_increment,
name varchar(20) NOT NULL unique,
teacher_id int(11) NOT NULL,
FOREIGN KEY (teacher_id) REFERENCES teacher (id)
);
CREATE TABLE studentcourse (
student_id int NOT NULL,
course_id int NOT NULL,
score double NOT NULL,
FOREIGN KEY (student_id) REFERENCES student (id),
FOREIGN KEY (course_id) REFERENCES course (id)
);
insert into teacher values(null,'关羽');
insert into teacher values(null,'张飞');
insert into teacher values(null,'赵云');
insert into student values(null,'小王','北京',20);
insert into student values(null,'小李','上海',18);
insert into student values(null,'小周','北京',22);
insert into student values(null,'小刘','北京',21);
insert into student values(null,'小张','上海',22);
insert into student values(null,'小赵','北京',17);
insert into student values(null,'小蒋','上海',23);
insert into student values(null,'小韩','北京',25);
insert into student values(null,'小魏','上海',18);
insert into student values(null,'小明','广州',20);
insert into course values(null,'语文',1);
insert into course values(null,'数学',1);
insert into course values(null,'生物',2);
insert into course values(null,'化学',2);
insert into course values(null,'物理',2);
insert into course values(null,'英语',3);
insert into studentcourse values(1,1,80);
insert into studentcourse values(1,2,90);
insert into studentcourse values(1,3,85);
insert into studentcourse values(1,4,78);
insert into studentcourse values(2,2,53);
insert into studentcourse values(2,3,77);
insert into studentcourse values(2,5,80);
insert into studentcourse values(3,1,71);
insert into studentcourse values(3,2,70);
insert into studentcourse values(3,4,80);
insert into studentcourse values(3,5,65);
insert into studentcourse values(3,6,75);
insert into studentcourse values(4,2,90);
insert into studentcourse values(4,3,80);
insert into studentcourse values(4,4,70);
insert into studentcourse values(4,6,95);
insert into studentcourse values(5,1,60);
insert into studentcourse values(5,2,70);
insert into studentcourse values(5,5,80);
insert into studentcourse values(5,6,69);
insert into studentcourse values(6,1,76);
insert into studentcourse values(6,2,88);
insert into studentcourse values(6,3,87);
insert into studentcourse values(7,4,80);
insert into studentcourse values(8,2,71);
insert into studentcourse values(8,3,58);
insert into studentcourse values(8,5,68);
insert into studentcourse values(9,2,88);
insert into studentcourse values(10,1,77);
insert into studentcourse values(10,2,76);
insert into studentcourse values(10,3,80);
insert into studentcourse values(10,4,85);
insert into studentcourse values(10,5,83);
根据上述的4张表练习:
-- 1、查询平均成绩大于70分的同学的学号和平均成绩
SELECT s.student_id,ROUND(avg(s.score),2) FROM studentcourse s GROUP BY s.student_id HAVING avg(s.score) > 70;
-- 2、查询所有同学的学号、姓名、选课数、总成绩
SELECT s.id '学号', s.`name` '姓名', COUNT(t.course_id) '选课数',ROUND(SUM(t.score),2) '总成绩' FROM student s LEFT JOIN studentcourse t ON s.id = t.student_id GROUP BY s.id;
-- 3、查询学过赵云老师所教课的同学的学号、姓名
SELECT s.id, s.`name` FROM student s LEFT JOIN studentcourse t ON s.id = t.student_id LEFT JOIN course c ON t.course_id = c.id LEFT JOIN teacher e ON c.teacher_id = e.id WHERE e.`name` = '赵云' GROUP BY s.id;
-- 4、查询没学过关羽老师课的同学的学号、姓名
SELECT * FROM student WHERE id NOT in (SELECT student_id FROM studentcourse WHERE course_id in (SELECT c.id FROM course c LEFT JOIN teacher t ON c.teacher_id = t.id WHERE t.`name` = '关羽') GROUP BY student_id);
-- 5、查询没有学三门课以上的同学的学号、姓名
SELECT s.id, s.`name` FROM student s LEFT JOIN studentcourse st ON s.id = st.student_id GROUP BY st.student_id HAVING COUNT(st.course_id)<3
-- 6、查询各科成绩最高和最低的分
SELECT c.name, MAX(score),MIN(score) FROM studentcourse s LEFT JOIN course c ON s.course_id = c.id GROUP BY s.course_id;
-- 7、查询学生信息和平均成绩
SELECT s.*, ROUND(AVG(st.score),2) FROM student s LEFT JOIN studentcourse st ON s.id = st.student_id GROUP BY st.student_id
-- 8、查询上海和北京学生数量
SELECT city, COUNT(*) FROM student GROUP BY city HAVING city in ('上海','北京');
-- 9、查询不及格的学生信息和课程信息
SELECT s.*, c.* FROM studentcourse st LEFT JOIN student s ON st.student_id = s.id LEFT JOIN course c ON st.course_id = c.id WHERE st.score < 60
-- 10、统计每门课程的学生选修人数(超过四人的进行统计)
SELECT c.`name`,COUNT(st.student_id) FROM studentcourse st LEFT JOIN course c ON st.course_id = c.id GROUP BY st.course_id HAVING COUNT(st.student_id) > 4
2、部门员工查询练习
准备工作:
-- 部门表
create table dept(
deptno int primary key auto_increment, -- 部门编号
dname varchar(14) , -- 部门名字
loc varchar(13) -- 地址
) ;
-- 员工表
create table emp(
empno int primary key auto_increment,-- 员工编号
ename varchar(10), -- 员工姓名 -
job varchar(9), -- 岗位
mgr int, -- 直接领导编号
hiredate date, -- 雇佣日期,入职日期
sal int, -- 薪水
comm int, -- 提成
deptno int not null, -- 部门编号
foreign key (deptno) references dept(deptno)
);
insert into dept values(10,'财务部','北京');
insert into dept values(20,'研发部','上海');
insert into dept values(30,'销售部','广州');
insert into dept values(40,'行政部','深圳');
insert into emp values(7369,'刘一','职员',7902,'1980-12-17',800,null,20);
insert into emp values(7499,'陈二','推销员',7698,'1981-02-20',1600,300,30);
insert into emp values(7521,'张三','推销员',7698,'1981-02-22',1250,500,30);
insert into emp values(7566,'李四','经理',7839,'1981-04-02',2975,null,20);
insert into emp values(7654,'王五','推销员',7698,'1981-09-28',1250,1400,30);
insert into emp values(7698,'赵六','经理',7839,'1981-05-01',2850,null,30);
insert into emp values(7782,'孙七','经理',7839,'1981-06-09',2450,null,10);
insert into emp values(7788,'周八','分析师',7566,'1987-06-13',3000,null,20);
insert into emp values(7839,'吴九','总裁',null,'1981-11-17',5000,null,10);
insert into emp values(7844,'郑十','推销员',7698,'1981-09-08',1500,0,30);
insert into emp values(7876,'郭靖','职员',7788,'1987-06-13',1100,null,20);
insert into emp values(7900,'令狐冲','职员',7698,'1981-12-03',950,null,30);
insert into emp values(7902,'张无忌','分析师',7566,'1981-12-03',3000,null,20);
insert into emp values(7934,'杨过','职员',7782,'1983-01-23',1300,null,10);
练习:
-- 1.列出至少有一个员工的所有部门。
SELECT DISTINCT deptno FROM emp;
-- 执行
SELECT * FROM dept WHERE deptno in(SELECT DISTINCT deptno FROM emp);
-- 2.列出薪金比"刘一"多的所有员工。
-- 刘一薪金
SELECT sal FROM emp WHERE ename='刘一';
-- 执行
SELECT * FROM emp WHERE sal>(SELECT sal FROM emp WHERE ename='刘一');
-- 3.列出所有员工的姓名及其直接上级的姓名。
-- 查出员工的姓名和年龄
SELECT ename,mgr FROM emp ;
-- 执行
SELECT temp.ename 员工名,emp.ename 领导 from emp,(SELECT ename,mgr FROM emp) as temp WHERE temp.mgr = emp.empno;
-- 4.列出受雇日期早于其直接上级的所有员工。
SELECT temp.ename 员工名,temp.hiredate 员工如期, emp.ename 领导,emp.hiredate 领导日期 from emp,(SELECT ename,mgr,hiredate FROM emp) as temp WHERE temp.mgr = emp.empno AND temp.hiredate < emp.hiredate;
-- 5.列出部门名称和这些部门的员工信息,同时列出那些没有员工的部门。
-- 使用左外链接显示左表中的全部信息
SELECT * FROM dept LEFT OUTER JOIN emp ON dept.deptno = emp.deptno;
-- 6.列出所有job为“职员”的姓名及其部门名称。
SELECT emp.ename,dept.dname FROM dept,emp WHERE job = '职员' AND emp.deptno = dept.deptno;
-- 7.列出最低薪金大于1500的各种工作。
SELECT job,sal from emp GROUP BY job HAVING sal > 1500;
-- 8.列出在部门 "销售部" 工作的员工的姓名,假定不知道销售部的部门编号。
-- 销售部id
SELECT deptno FROM dept WHERE dname = '销售部';
SELECT ename FROM emp WHERE deptno = (SELECT deptno FROM dept WHERE dname = '销售部');
-- 9.列出薪金高于公司平均薪金的所有员工。
-- 平均薪金
SELECT avg(sal) FROM emp;
SELECT * FROM emp WHERE sal > (SELECT avg(sal) FROM emp);
-- 10.列出与"周八"从事相同工作的所有员工。
SELECT job FROM emp WHERE ename = '周八';
SELECT * FROM emp WHERE job = (SELECT job FROM emp WHERE ename = '周八');
-- 11.列出薪金等于部门30中员工的薪金的所有员工的姓名和薪金。
-- 12.列出薪金高于在部门30工作的所有员工的薪金的员工姓名和薪金。
-- 部门30最高薪金
SELECT MAX(sal) FROM emp WHERE deptno = 30;
SELECT ename,sal FROM emp WHERE sal > (SELECT MAX(sal) FROM emp WHERE deptno = 30);
-- 13.列出在每个部门工作的员工数量、平均工资。
SELECT count(*),avg(sal) FROM emp GROUP BY deptno
-- 14.列出所有员工的姓名、部门名称和工资。
SELECT emp.ename,emp.sal,dept.dname FROM dept,emp WHERE dept.deptno = emp.deptno;
-- 15.列出所有部门的详细信息和部门人数。
-- 部门人数
SELECT COUNT(*) FROM emp GROUP BY deptno;
-- 执行
SELECT * FROM dept,(SELECT deptno,COUNT(*) 员工总人数 FROM emp GROUP BY deptno) AS temp WHERE dept.deptno = temp.deptno;
-- 16.列出各种工作的最低工资。
SELECT MIN(sal) FROM emp GROUP BY job;
-- 17.列出各个部门的 经理 的最低薪金。
-- 部门最低薪金
SELECT job,MIN(sal),deptno FROM emp where job = '经理' GROUP BY deptno;
-- 18.列出所有员工的年工资,按年薪从低到高排序。
SELECT ename,sal*12 FROM emp ORDER BY sal DESC
-- 19.查出emp表中薪水在3000以上(包括3000)的所有员工的员工号、姓名、薪水。
SELECT empno,ename,sal FROM emp WHERE sal >= 3000;
-- 20.查询出所有薪水在'陈二'之上的所有人员信息。
SELECT sal FROM emp WHERE ename = '陈二';
SELECT * FROM emp WHERE sal > (SELECT sal FROM emp WHERE ename = '陈二');
-- 21.查询出emp表中部门编号为20,薪水在2000以上(不包括2000)的所有员工,显示他们的员工号,姓名以及薪水,以如下列名显示:员工编号 员工名字 薪水
SELECT empno 员工编号,ename 员工名字,sal 薪水 from emp WHERE deptno = 20 and sal > 2000 ;
-- 22.查询出emp表中所有的工作种类(无重复)
SELECT DISTINCT job 工作种类 FROM emp
-- 23.查询出所有奖金(comm)字段不为空的人员的所有信息。
SELECT * FROM emp WHERE comm is not null;
-- 24.查询出薪水在800到2500之间(闭区间)所有员工的信息。(注:使用两种方式实现and以及between and)
SELECT * FROM emp WHERE sal BETWEEN 800 AND 2500;
-- 25.查询出员工号为7521,7900,7782的所有员工的信息。(注:使用两种方式实现,or以及in)
SELECT * from emp WHERE empno in(7521,7900,7782);
SELECT * from emp WHERE empno = 7521 OR empno = 7900 OR empno = 7782;
-- 26.查询出名字中有“张”字符,并且薪水在1000以上(不包括1000)的所有员工信息。
SELECT * FROM emp WHERE sal > 1000 AND ename LIKE '%张%'
-- 27.查询出名字第三个汉字是“忌”的所有员工信息。
SELECT * FROM emp WHERE ename LIKE '__忌';
-- 28.将所有员工按薪水升序排序,薪水相同的按照入职时间降序排序。
SELECT * FROM emp ORDER BY sal ASC,hiredate DESC;
-- 29.将所有员工按照名字首字母升序排序,首字母相同的按照薪水降序排序。 order by convert(name using gbk) asc;
SELECT * FROM emp order by convert(ename using gbk) asc,sal DESC;
-- 30.查询出最早工作的那个人的名字、入职时间和薪水。
SELECT MIN(hiredate) FROM emp;
SELECT ename 名字,hiredate 入职时间,sal 薪水 FROM emp WHERE hiredate = (SELECT MIN(hiredate) FROM emp);
-- 31.显示所有员工的名字、薪水、奖金,如果没有奖金,暂时显示100.
SELECT ename,sal,(case when comm is null then 100 else comm end ) FROM emp;
-- 32.显示出薪水最高人的职位。
SELECT job FROM emp WHERE sal = (SELECT MAX(sal) FROM emp );
-- 33.查出emp表中所有部门的最高薪水和最低薪水,部门编号为10的部门不显示。
SELECT deptno,MAX(sal),MIN(sal) FROM emp GROUP BY deptno HAVING deptno != 10;
-- 34.删除10号部门薪水最高的员工。
-- 10号部门薪水最高的员工
SELECT empno,MAX(sal) FROM emp WHERE deptno = 10;
-- 删除
delete from emp where empno = (select empno from (select empno from emp where deptno = 10 ORDER BY sal desc limit 1) t);
-- 35.将薪水最高的员工的薪水降30%。
SELECT MAX(sal) FROM emp
UPDATE emp SET sal = (SELECT sal FROM (SELECT MAX(sal) FROM emp) tt)*(1-0.3) WHERE empno = (SELECT empno FROM (SELECT empno FROM emp ORDER BY sal DESC LIMIT 1) t);
-- 36.查询员工姓名,工资和 工资级别(工资>=3000 为3级,工资>2000 为2级,工资<=2000 为1级)
-- 语法:case when ... then ... when ... then ... else ... end
SELECT ename 员工姓名, sal 工资,(CASE WHEN sal > 3000 THEN '3级' WHEN sal <= 2000 THEN '1级' ELSE '2级'END) 工资级别 FROM emp WHERE 1 = 1;
3、在sql中获取当前时间
INSERT INTO tb_user (id,user_name,PASSWORD,created,updated)VALUES(NULL,'zs',111111,NOW(),NOW())
4、添加随机uuid
insert into table1"(id,name,age) value(uuid(),''张三“,18)
901

被折叠的 条评论
为什么被折叠?



