[leetcode]412. Fizz Buzz

最新推荐文章于 2021-10-14 08:52:51 发布

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最新推荐文章于 2021-10-14 08:52:51 发布

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本文介绍了一个简单的编程挑战，即实现FizzBuzz程序。该程序从1数到n，但遇到3的倍数输出Fizz，5的倍数输出Buzz，同时为3和5的倍数时输出FizzBuzz。通过Java代码示例展示了如何优雅地解决这个问题。

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Write a program that outputs the string representation of numbers from 1 to n.

But for multiples of three it should output “Fizz” instead of the number and for the multiples of five output “Buzz”. For numbers which are multiples of both three and five output “FizzBuzz”.

Example:

n = 15,

Return:
[
    "1",
    "2",
    "Fizz",
    "4",
    "Buzz",
    "Fizz",
    "7",
    "8",
    "Fizz",
    "Buzz",
    "11",
    "Fizz",
    "13",
    "14",
    "FizzBuzz"
]

Solution:

class Solution {
    public List<String> fizzBuzz(int n) {
        List<String> list = new ArrayList<String>();
        for(int i = 1; i <= n; i++) {
            if(i%3 == 0 && i%5 ==0) {
                list.add("FizzBuzz");
            }else if(i%3 == 0) {
                list.add("Fizz");
            }else if(i%5 ==0) {
                list.add("Buzz");
            }else {
                list.add(String.valueOf(i));
            }
        }
        return list;
    }
}